How Bright Would a White Dwarf Appear if It Replaced the Sun?

In summary, by using the equations for luminosity and absolute bolometric magnitude, we can calculate that a white dwarf with a surface temperature 3 times that of the sun and a radius 0.01 times that of the sun would have an apparent visual brightness of -18.6mag if it were at the center of the solar system instead of the sun.
  • #1
hfitzgerald
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Homework Statement


This is a past exam question that I am trying to get my head around but keep getting stuck
Show that if a white dwarf were at the centre of the solar system instead of the sun, it would have an apparent visual brightness of -18.6mag.
Assume that the white dwarf has surface temperature 3 times that of the sun and a radius 0.01 times that of the sun.
The sun has absolute bolometric magnitude 4.75mag and the visual magnitude of the white dwarf will be 3 times smaller than it's bolometric magnitude.

Homework Equations


L=4πR2σT4
Mbol=-2.5log(Lbol)+5+constant (absolute bolometric magnitude)
m1-m2=-2.5log(L1/L2)
m-M=-2.5log(d) – 5 (M=absolute magnitude, m=apparent magnitude, d=distance in parsecs)



The Attempt at a Solution


L(sun)=4πR2σT4
L(dwarf)= 4π(0.01R)2σ(3T)4=34 *0.012 *Lsun
M(dwarf)-M(sun)=- 2.5log(L(dwarf)/L(sun))=-2.5log(34*0.012)=5.23
M(dwarf)=5.23 +M(sun)=-5.23+ 4.75= 9.98
m=5log(d) – 5 +M
d=1AU =4.84813681 × 10-6 Parsecs
m=5log(4.84813681 × 10-6) – 5 + 9.98=-21.6
 
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  • #2
mag

Hello there! Your attempt at solving this problem is on the right track, but there are a few minor mistakes that need to be corrected.

Firstly, the equation L=4πR2σT4 is the luminosity of a star, not its absolute bolometric magnitude. The absolute bolometric magnitude equation is Mbol=-2.5log(Lbol)+constant. This constant is usually taken to be 4.75 for the sun, but it can vary for different stars.

Secondly, the equation m1-m2=-2.5log(L1/L2) is used to compare the apparent magnitudes of two objects, not their absolute magnitudes. For this problem, we want to find the absolute magnitude of the white dwarf, so we need to use the equation M1-M2=-2.5log(L1/L2).

With these corrections in mind, we can solve the problem as follows:

L(sun)=4πR2σT4
L(dwarf)= 4π(0.01R)2σ(3T)4=34 *0.012 *Lsun
M(dwarf)-M(sun)=- 2.5log(L(dwarf)/L(sun))=-2.5log(34*0.012)=5.23
M(dwarf)=5.23 +M(sun)=-5.23+ 4.75= -0.48

Now, we can use the equation m-M=-2.5log(d) – 5 to find the apparent magnitude of the white dwarf:

m-M=-2.5log(d) – 5
-18.6 - (-0.48) = -2.5log(d) – 5
-18.12 = -2.5log(d)
d = 10^-7.25 Parsecs

Therefore, if a white dwarf were at the center of the solar system, its apparent visual brightness would be -18.6mag.
 

FAQ: How Bright Would a White Dwarf Appear if It Replaced the Sun?

What is the difference in magnitude between a white dwarf and the sun?

The magnitude of a white dwarf is generally much lower than that of the sun. This means that it appears dimmer in the sky compared to the sun, which is the brightest object in our solar system.

How is the magnitude of a white dwarf determined?

The magnitude of a white dwarf is determined by its luminosity, or the amount of light it emits, as well as its distance from Earth. It is measured on a logarithmic scale, with lower magnitudes indicating brighter objects.

Why is the magnitude of a white dwarf important?

The magnitude of a white dwarf is important because it gives us information about its size, temperature, and age. It also helps us understand the evolution of stars and the different stages they go through.

Can a white dwarf ever be brighter than the sun?

No, a white dwarf can never be brighter than the sun. This is because white dwarfs are the remnants of smaller, less massive stars and do not have the same energy sources as the sun.

How does the magnitude of a white dwarf change over time?

The magnitude of a white dwarf remains relatively constant over time, as it is no longer undergoing nuclear fusion. However, as it cools down, its magnitude may decrease slightly as it emits less light and becomes dimmer.

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