- #1
nofunatall
- 3
- 0
How do you find the derivative of the following?
e^5X - 3log(x)
e^5X - 3log(x)
Zurtex said:Do you know how to use the chan rule and what the derivative of a log is?
~No, that's not true;Zurtex said:Well:
[tex]\frac{d}{dx} ( \log x ) = \frac{1}{x} \quad \text{for all} \, x > 0[/tex]
Not in all cases. For example, it is usual in analysis to use just log to mean base e. Sadly, this does cause some confusion, so people really should write the base when there's no context.bomba923 said:The natural logarithm of [itex]x[/itex] is written as [itex]\ln(x)[/itex], not [itex]\log(x)[/itex].
How horrid, and utterly dumb.0rthodontist said:My algorithms textbook uses three different kinds of logarithm, log, ln, and lg for base 2.
The derivative of e^5x is 5e^5x.
To find the derivative of e^5x - 3log(x), you would use the power rule for the first term (e^5x) and the quotient rule for the second term (3log(x)).
Yes, the derivative can be simplified to 5e^5x - 3/x.
No, the derivative can be positive, negative, or zero depending on the value of x.
The derivative of e^5x - 3log(x) increases as x increases. This can be seen by the fact that the first term (e^5x) is always positive and the second term (3log(x)) decreases as x increases.