- #1
simoncastle
- 1
- 0
Hi all,
Here's the problem!
I am attempting to create a leakage current test suite. Basically it centers around cutting the voltage reference supply to a capacitor and measuring the voltage drop. Similar to the one in the attachment.
I figured that to determine the drop it would be a simple case of V at start minus V after time delay.
However a colleage told me that because of the exponential decay of capacitors this simple equation wouldn't be enough to accuratly determine the voltage drop.
Any ideas?
Thanks!
- Si
Here's the problem!
I am attempting to create a leakage current test suite. Basically it centers around cutting the voltage reference supply to a capacitor and measuring the voltage drop. Similar to the one in the attachment.
I figured that to determine the drop it would be a simple case of V at start minus V after time delay.
However a colleage told me that because of the exponential decay of capacitors this simple equation wouldn't be enough to accuratly determine the voltage drop.
Any ideas?
Thanks!
- Si