- #1
HazyMan
- 51
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The problem says: A radio station emits electromagnetic wave with a frequency of 100MHz (102*106 Hz).
a)What's the energy of this radiation's/glow's photon? (Solved, i found 6,63*10-26 J)
b)Compare your calculation with the energy of another visible radiation/glow, with a wavelength of 600nm (6*102*10-9 m). (Solved as well, found 3,315*10-19 J)
c) and the part that BUGS me, FIND THE NUMBER OF PROTONS EMITTED IN 1 SECOND, IF THE RADIATED/GLOWED POWER IS 6,63kW (6,63*103 W)
The problem with this question is that i came up with this formula: N=t(h*f/P) where N is the number of the photons and P the power. Using this i came up with 10-37 which confuses me, because my teacher had used a different way and found 1029. He took the E=pt formula and turned it into E=N*Ep (Ep is the photon energy that was calculated in question a) and then he created a N=E/Ep [or N=(P*t/Ep)] where he got HIS result from. Can anyone help me? I'm confused.
OTHER EQUATIONS USED: Ep=hf, f2=Co/λο (where f2 is the freq. of the other radiation/glow from question b), Ep2=hf2 (where Ep2 is the photon energy of the other radiation/glow from question b).
a)What's the energy of this radiation's/glow's photon? (Solved, i found 6,63*10-26 J)
b)Compare your calculation with the energy of another visible radiation/glow, with a wavelength of 600nm (6*102*10-9 m). (Solved as well, found 3,315*10-19 J)
c) and the part that BUGS me, FIND THE NUMBER OF PROTONS EMITTED IN 1 SECOND, IF THE RADIATED/GLOWED POWER IS 6,63kW (6,63*103 W)
The problem with this question is that i came up with this formula: N=t(h*f/P) where N is the number of the photons and P the power. Using this i came up with 10-37 which confuses me, because my teacher had used a different way and found 1029. He took the E=pt formula and turned it into E=N*Ep (Ep is the photon energy that was calculated in question a) and then he created a N=E/Ep [or N=(P*t/Ep)] where he got HIS result from. Can anyone help me? I'm confused.
OTHER EQUATIONS USED: Ep=hf, f2=Co/λο (where f2 is the freq. of the other radiation/glow from question b), Ep2=hf2 (where Ep2 is the photon energy of the other radiation/glow from question b).