- #1
Sorin2225
- 20
- 1
- Homework Statement
- Started with a 0.1g of cesium-137, decayed into ba-137 after twelve hours by beta decay, this starts to decay with gamma rays. 12 hours after this someone pockets the sample and absorbs 50% of the beta particles and 10% of the gamma rays. How would I find the rate at which they are absorbing energy.
- Relevant Equations
- beta energy=0.512MeV
Gamma energy=0.6617MeV
Rate of Beta and gamma radiation=3.2*10^11
Problem Statement: Started with a 0.1g of cesium-137, decayed into ba-137 after twelve hours by beta decay, this starts to decay with gamma rays. 12 hours after this someone pockets the sample and absorbs 50% of the beta particles and 10% of the gamma rays. How would I find the rate at which they are absorbing energy.
Relevant Equations: beta energy=0.512MeV
Gamma energy=0.6617MeV
Rate of Beta and gamma radiation=3.2*10^11
Assuming it is 10% and 50% of the particles been released at 12 hours. So 10% of gamma = 3.2*10^10
50% of gamma = 1.6*10^11. This is how many particles are been emitted. Energy is per photon so 3.2*10^10 * 0.6617*10^6, 1.6*10^11* 0.512*10^6.. Energy of Gamma=2.11744*10^16. Energy of Beta= 8.192*10^16. Thus total energy would be these two added = 1.031*10^17. Over twelve hours so 8.59*10^15. I have no idea if this is even on the right track. The only other way I can think of doing it would be finding out the mass difference after the decay and using E=mc^2 but I assume I don't use that because I was given the energies.
Relevant Equations: beta energy=0.512MeV
Gamma energy=0.6617MeV
Rate of Beta and gamma radiation=3.2*10^11
Assuming it is 10% and 50% of the particles been released at 12 hours. So 10% of gamma = 3.2*10^10
50% of gamma = 1.6*10^11. This is how many particles are been emitted. Energy is per photon so 3.2*10^10 * 0.6617*10^6, 1.6*10^11* 0.512*10^6.. Energy of Gamma=2.11744*10^16. Energy of Beta= 8.192*10^16. Thus total energy would be these two added = 1.031*10^17. Over twelve hours so 8.59*10^15. I have no idea if this is even on the right track. The only other way I can think of doing it would be finding out the mass difference after the decay and using E=mc^2 but I assume I don't use that because I was given the energies.
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