- #1
Dweirdo
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OMG second time I'm opening a thread in the wrong forum FFS!
Damn bookmarks! MODS move it please.
Not a home work question, just something i cam across and need a clarification.
Could One show me how to derive to the equation that X(cm)=int(X dm)/M
int=the deformed S of the integral(2 lazy to write in Latex XD).
X(cm)=sigma(Xi Dmi)/M
I know It's simple, But I can't imagine how sigma(Xi Dmi) becomes int(X dm),
I don't understand what it means , trying to convert it to words just doesn't work for me,so could some 1 explain that for me?
AFAIK sigma(Xi Dmi) means the mass distribution,but how does the integral takes place here?
I really need to understand the math part in physics.
Thanks a lot in advanced !
Damn bookmarks! MODS move it please.
Homework Statement
Not a home work question, just something i cam across and need a clarification.
Could One show me how to derive to the equation that X(cm)=int(X dm)/M
int=the deformed S of the integral(2 lazy to write in Latex XD).
Homework Equations
X(cm)=sigma(Xi Dmi)/M
The Attempt at a Solution
I know It's simple, But I can't imagine how sigma(Xi Dmi) becomes int(X dm),
I don't understand what it means , trying to convert it to words just doesn't work for me,so could some 1 explain that for me?
AFAIK sigma(Xi Dmi) means the mass distribution,but how does the integral takes place here?
I really need to understand the math part in physics.
Thanks a lot in advanced !
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