How can I express SQRT(27) in terms of i and cancel out the i?

In summary, the conversation revolves around solving for x and finding the form of SQRT(27) that will allow for further simplification. The conversation also delves into the use of Euler's sine formula and the concept of cosine being equal to sine. However, the conclusion is that SQRT(27) simplifies to 3sqrt(3) and any attempt to prove otherwise is incorrect.
  • #1
GreenPrint
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Homework Statement



I was trying to do this problem and noticed that I should be able to express SQRT(27) in terms of i and cancle out the i making it more simple I can't seem to remember how to do this thanks

[IMG=http://img294.imageshack.us/img294/5396/captureow.jpg][/PLAIN]

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Homework Equations





The Attempt at a Solution

 
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  • #2
here you go sorry about that

[PLAIN]http://img294.imageshack.us/img294/5396/captureow.jpg

i need to solve for x don't remeber how to do this
 
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  • #4
If you're looking for the solutions to x2 - 27 = 0, they are the real numbers [itex]x = 3\sqrt{3}[/itex] and [itex]x = -3\sqrt{3}[/itex]. Otherwise, I have no idea what you're trying to do.
 
  • #5
I think i may have just proved
SQRT(27) = -27
did something wrong but I did it step by step let me look at this :(
 
  • #6
I'll show you in a moment I think i may have just proved SQRT(27) = -27
I don't think I have done anything wrong this is really weird let me type it up... hope I'll find something wrong because if i don't... :O
 
  • #7
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  • #8
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  • #9
but you that form is better to use becasue then you can cancel out the pi and your left with i raised to some fraction much easier to evalute no? but you i guess i misse dup some where and did it wrong but it works
 
  • #10
well that sure is strange I never was taught that form of sin I just wen through the derrivation i guess of euelr's sine formula and screwed up somewhere but it's right

wounder why I have never encountered it before i think it would be much easier to use no
 
  • #11
I think I have messed up when I did SQRT(3) as an example sorry
 
  • #12
Well see what I think I need to do is take my sine equation and set it equal to sqrt(37) sine can take on any value those who say it's llimited betweeen 1 and negative one are liers... and then solve so when solved earlier I think I was doing it right I thinkI just need to start over
 
  • #13
well i guess in theory I should have just done this

http://img706.imageshack.us/img706/4708/capturefeb.jpg

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and solved for x since sine can take on any value it wants then just do sin(x) would truly be the most simplifed huh?
I think that would be a better way to do it instead of setting it equal to sqrt(27) yes I know realize I forgot the initial 1/2 when I original atempted and set it eqaul to sqrt(27) so should i set it equal to sqrt(27) or just the whole darn thing
 
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  • #14
I take that back what I originally did wasn't wrong as that should be able to take on any number that it desires as well no and then I could cancel out the i if I had one in the denomenator, in post number seven I guess I just did something wrong...
 
  • #15
well i just had this great idea that I'm going to work out tommarow I am going to set cosine=sine
yes that's
cos(x)=sin(x)
or in common terms what angle does cosine and sine have the same value... none? Don't think so my friend I'm not buying it... I just woundering what will happen I am going to solve it...

sorry by the way i started out trying to do that problem then got into sine and this idea just poped into my head and was like well i should be able to solve that technically speaking...

well i just did it everything canceled out I wounder what that means oh crap maybe you guys were right there is none =(
 
  • #16
GreenPrint said:
I think i may have just proved
SQRT(27) = -27

This is ridiculous. If this were true, the 27 = (-27)2 would also be true. Obviously, it isn't.

sqrt(27) is not a complex number, so why are you even bothering to go down that path?

In its simplest form, sqrt(27) is 3sqrt(3).
 

FAQ: How can I express SQRT(27) in terms of i and cancel out the i?

What are complex numbers?

Complex numbers are numbers that contain both a real and imaginary component. They are written in the form a + bi, where a is the real part and bi is the imaginary part. The imaginary unit, i, is equal to the square root of -1.

How do you add or subtract complex numbers?

To add or subtract complex numbers, you simply combine the real parts and the imaginary parts separately. For example, (3+2i) + (5+4i) = (3+5) + (2+4)i = 8 + 6i. Similarly, (3+2i) - (5+4i) = (3-5) + (2-4)i = -2 - 2i.

What is the difference between a complex number and an imaginary number?

An imaginary number is a complex number with a zero real component. In other words, it can be written in the form bi, where b is a real number and i is the imaginary unit. A complex number, on the other hand, has both a real and imaginary component.

How do you multiply or divide complex numbers?

To multiply complex numbers, you use the FOIL method, just like you would for binomials. For example, (3+2i)(5+4i) = 15 + 12i + 10i + 8i^2 = 15 + 22i - 8 = 7 + 22i. To divide complex numbers, you use the conjugate of the denominator to eliminate the imaginary part. For example, (3+2i) / (5+4i) = (3+2i)(5-4i) / (5+4i)(5-4i) = (15-8i) / (25+16) = 15/41 - 8/41i.

How are complex numbers used in real life?

Complex numbers are used in many areas of science and engineering, such as electrical engineering, signal processing, and quantum mechanics. They are also used in everyday applications, such as in the design of computer graphics and in the study of chaotic systems. Additionally, complex numbers are used in financial mathematics and in solving certain types of differential equations.

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