How can I obtain real lengths for 'r' in the equation of a circle when R > A?

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In summary, the individual is having trouble using the equation of a circle to describe a geometry in their research project. They are getting complex lengths for 'r' due to the negative term in the square root, and are asking for an explanation and solution to obtain real lengths for 'r'. The equation is r = Rcos(theta)+sqrt(A^2-(Rsin(theta))^2), where R is the distance from the origin to the center of the circle and A is the radius. This issue occurs when R > A and the value of theta is too large, resulting in no intersection between the radial line and the circle. More information and helpful resources can be found at the provided link.
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tanderse
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Right now, I need to use the equation of a circle to describe a geometry I'm dealing with in a research project. For some reason, I cannot make sense of it, and it is extremely frustrating... Right now I'm using:

r = Rcos(theta)+sqrt(A^2-(Rsin(theta))^2)

where R is the distance from the origin to the center of the circle and A is the radius of the circle. Assume the center of the circle lies on the polar axis. I keep getting complex lengths for 'r', which obviously comes from the negative term in the square root. Can someone explain to me in a physical sense why this is happening? And my main question is how can I make it so I only obtain proper, real lengths for 'r'? Any help is appreciated
 
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  • #2
What do r and theta represent? We can't tell you why your equation is giving you non-nonsensical answers if we don't know what it is, in principle, supposed to mean. Where did your equation come from?
 
  • #3
In short, you are dealing with the case where R > A. In this case, value of [tex]\theta[/tex] cannot be arbitrary. If the value of [tex]\theta[/tex] is too large, there will be no intersection between the radial line and the circle.

Please refer to this http://www.voofie.com/content/78/why-do-i-get-imaginary-value-for-radius-from-equation-of-circle-in-polar-coordinate/" , which has nice graphs and detailed steps to illustrate the situation.
 
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FAQ: How can I obtain real lengths for 'r' in the equation of a circle when R > A?

What is the equation of a circle?

The equation of a circle is a mathematical representation of a circle, which is a set of points in a plane that are equidistant from a given point called the center. The standard form of the equation of a circle is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle and r is the radius.

How do you find the center of a circle from its equation?

To find the center of a circle from its equation, you can rearrange the standard form of the equation to the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center point. The values of h and k can be found by taking the opposite sign and value of the coefficients of x and y, respectively.

What is the significance of the radius in the equation of a circle?

The radius in the equation of a circle represents the distance from the center of the circle to any point on its circumference. It is a crucial component in determining the size and position of a circle.

Can the equation of a circle be used to find the area and circumference of a circle?

Yes, the equation of a circle can be used to find the area and circumference of a circle. The area of a circle can be calculated using the formula A = πr^2, where r is the radius of the circle. The circumference of a circle can be calculated using the formula C = 2πr, where r is the radius of the circle.

Can the equation of a circle be applied to a 3-dimensional space?

Yes, the equation of a circle can be applied to a 3-dimensional space. In this case, the equation would be in the form (x - h)^2 + (y - k)^2 + (z - l)^2 = r^2, where (h, k, l) is the center of the circle and r is the radius. This equation represents a sphere, which is the 3-dimensional analogue of a circle.

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