- #1
tmt1
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- 0
I have this integral
$$6\int_{}^{} \frac{u^3 - 1 + 1}{u - 1}\,d$$
And I need to simplify it to
$$6\int_{}^{}u^2 + u + 1 \frac{1}{u - 1}\,du$$
But I don't know how to get to this step.
$$6\int_{}^{} \frac{u^3 - 1 + 1}{u - 1}\,d$$
And I need to simplify it to
$$6\int_{}^{}u^2 + u + 1 \frac{1}{u - 1}\,du$$
But I don't know how to get to this step.