How Can I Solve for Tau in These Two Equations?

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In summary, you can solve for tau in terms of t1, t2, Vf, V1, and V2 by first solving each equation individually for tau and then equating the results. This will give you a relationship between the variables. Alternatively, you can solve for the exponential terms and divide them to get an expression for tau in terms of all 5 variables.
  • #1
Mugged
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I have these two equations:

V1 = Vf(1-e^(-t1/tau)) and V2 = Vf=(1-e^(-t2/tau))

I need to solve for tau in terms of t1, t2, Vf, V1, and V2 but i can't seem to find a proper way to combine these equations.

can you help?
 
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  • #2
You can solve each equation individually for tau. Then, since the results must be equal, you can equate them. This will give you a relationship between V1, t1, and V2, t2.

Example of solving one of the equations:

[tex] V_1 = V_f (1 - e^{-t_1 / \tau} ) [/tex]​

Divide both sides by Vf:

[tex] \frac{V_1}{V_f} = 1 - e^{-t_1 / \tau} [/tex]​

Subtract V1 / Vf from both sides. Then add the exponential term to both sides (in other words, rearrange the terms):

[tex] e^{-t_1 / \tau} = 1 - \frac{V_1}{V_f} [/tex]​

Take the natural logarithm of both sides of the equation:

[tex] -\frac{t_1}{\tau} = \ln \left[1 - \frac{V_1}{V_f} \right] [/tex]​

Solve for tau by multiplying both sides by tau and then dividing both sides by the ln term (in other words, cross-multiply):

[tex] \tau = -\frac{t_1}{\ln \left[1 - \frac{V_1}{V_f} \right]} [/tex]​

Now, when you solve the second equation for tau, you'll get a similar answer in terms of V2 and t2. Since it must be true that tau = tau, you can equate these results.
 
  • #3
erm, thanks, but i need tau in terms of all 5 variables, not just 3.

I shouldve made that clear; not hard to solve for tau using just 1 equation actually...
 
  • #4
Mugged said:
erm, thanks, but i need tau in terms of all 5 variables, not just 3.

I shouldve made that clear; not hard to solve for tau using just 1 equation actually...

Yeah, I know that. You should have read my post more closely. Do you agree with me, that using the exact same algebraic steps described in my first post, but applying them to the second equation (for V2), we will arrive at the following expression for tau?

[tex] \tau = -\frac{t_2}{\ln \left[1 - \frac{V_2}{V_f} \right]} [/tex]​

If so, then it must be true that:

[tex] \tau = -\frac{t_2}{\ln \left[1 - \frac{V_2}{V_f} \right]} = -\frac{t_1}{\ln \left[1 - \frac{V_1}{V_f} \right]} [/tex]​

EDIT: So basically V2, t2, V1, t1, can't all be independent variables. The equation above illustrates that they must be related to each other.
 
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  • #5
yeah that's mathematically correct no doubt...but definitely not what i asked.

actually i already solved it myself just now. if you solve for the e pieces and divide one over the other, you can solve for tau in terms of all variables.

thanks though ceph
 

FAQ: How Can I Solve for Tau in These Two Equations?

What is Tau and why is it used in equations?

Tau is a mathematical constant that is equal to 2π, or approximately 6.28. It is used in equations involving circles and cycles, as well as in trigonometry and other branches of mathematics.

How do I solve an equation for Tau?

To solve an equation for Tau, you will need to isolate it on one side of the equation using algebraic operations such as addition, subtraction, multiplication, and division. You may also need to use properties of logarithms or exponents, depending on the form of the equation.

Can I use a calculator to solve an equation for Tau?

Yes, you can use a calculator to solve an equation for Tau. However, it is important to ensure that you are using the correct input and order of operations to get an accurate result.

Are there any special rules or formulas for solving equations involving Tau?

There are no specific rules or formulas for solving equations involving Tau. You will need to use standard algebraic techniques and may also need to apply knowledge of logarithms and exponents, depending on the equation.

When should I use Tau instead of Pi in equations?

Tau is often used in place of Pi in equations involving circles and cycles, as it simplifies calculations and can make certain equations more intuitive. However, the use of Tau or Pi ultimately depends on the context and personal preference of the mathematician or scientist.

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