How can I understand the Thevenin Theorem and its formula for e?

In summary, the equation e = V1R3/(R1+R3) can be derived from Kirchhoff's rules. When nodes a and b are open, no current will flow through R2. Since there is no current through R2, there will be no voltage drop across R2. So therefore, the open circuit voltage is simply the voltage across R3. Which if you do KVL, or just a simple voltage divider equation, you'll get to the equation that's in question.
  • #1
thelovemonkey
12
0

Homework Statement



hey guys. I am new to the board. I've seen this problem on a website of which i'll list below. I am not sure how came up with that formula for e.


http://hyperphysics.phy-astr.gsu.edu/HBASE/electric/thevenin.html -> is the link to the page.

i understand the rest of the problem, thaz teh only thing thaz giving me a hard time. thanks in advance for ur helps. cheers.
 
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  • #2
Welcome to PF!

thelovemonkey said:
ive seen this problem on a website of which i'll list below. I am not sure how came up with that formula for e.

Hi thelovemonkey! Welcome to PF! :wink:

Do you mean e = V1R3/(R1 + R3) ?

Since no current is flowing through R2, the voltage across AB is the same as the voltage across R3, which you can calculate from Kirchhoff's rules :smile:
 
  • #3
oh okay okay i udnerstand that. but i don't quite understand the actual equation e = V1R3/(R1 + R3) as in how it was derived.
 
  • #4
When nodes a and b are open, no current will flow through R2. Since there is no current through R2, there will be no voltage drop across R2. So therefore, the open circuit voltage is simply the voltage across R3. Which if you do KVL, or just a simple voltage divider equation, you'll get to the equation that's in question.What does your Kirchoff equation look like?
 
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  • #5
aw man. i think that's my problem right there. i don't know about voltage divider equatiosn and stuff.
 
  • #6
Ok, try to sum up the current at the point between R1 and R3. We know from the link that tiny-kim gave us, that this summation will equal zero. Even more helpful is the formula V=I*R. , so we'll get something like ( V_oc / R3 ) as the current through the resistor R3. V_oc means Voltage of open circuit. Now what will the current be for R1? What is the voltage difference between the source voltage and V_oc? Then from there, what's the current knowing the resistance is R1? Is this current the same current as that flowing through R3? Why? Once you get an equation in terms of voltages and resistances, then it becomes some algebraic maneuvering to achieve the desired formula.

There's a a few details in dealing with whether or not the current's sign should be positive or negative, which can be addressed using the passive sign convention.

http://en.wikiversity.org/wiki/Passive_sign_convention There's a good link for you to look at and digest.
 
  • #7
hurray for b00bies i found it. this link helped sort the voltage divider thing for me
http://www.allaboutcircuits.com/vol_1/chpt_6/1.html

sorry guys no offence or anything. but i haven't understood quite clearly from the way you've explained. however. ur links and stuff were good reads and helped me out in other aspects of electricity.

im doing first year civil engineering and gotto do a semester of electronics.



BTW. anyone of u guys have an eFormula sheet for electronics?
 

FAQ: How can I understand the Thevenin Theorem and its formula for e?

What is Thevenin's Theorem?

Thevenin's Theorem is a fundamental principle in electrical engineering that states that any linear circuit can be simplified into an equivalent circuit with a single voltage source and a single resistance. This simplification makes it easier to analyze and solve complex circuits.

How do you calculate the Thevenin voltage and resistance?

To calculate the Thevenin voltage, you need to remove all sources from the circuit and calculate the voltage across the load. This voltage will be the Thevenin voltage. To calculate the Thevenin resistance, you need to remove all sources and short circuit the load. Then, calculate the equivalent resistance seen from the load terminals. This resistance will be the Thevenin resistance.

What are the limitations of Thevenin's Theorem?

Thevenin's Theorem is only applicable to linear circuits, meaning that it cannot be used for circuits with non-linear elements such as diodes. Additionally, it assumes that the circuit is operating in a steady-state condition and does not take into account any time-varying effects.

How is Thevenin's Theorem applied in real-world circuits?

Thevenin's Theorem is commonly used in circuit analysis and design. It allows engineers to simplify complex circuits and determine the behavior of the circuit under different conditions. This is useful in designing and troubleshooting electronic systems.

Can Thevenin's Theorem be used for AC circuits?

Yes, Thevenin's Theorem can be applied to both DC and AC circuits. However, the calculations for Thevenin voltage and resistance may differ for AC circuits due to the presence of capacitors and inductors. In AC circuits, the Thevenin resistance is the equivalent impedance seen from the load terminals.

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