How can I use the annihilator method to solve for 4e-2t*cos(2t)?

In summary, the conversation discusses using the annihilator method to solve for a differential equation involving 4e-2t*cos(2t). The suggested approach is to use the characteristic equation and its roots to find the appropriate annihilator for the given equation. However, the connection between etsin(3t) and etcos(3t) and the roots of the characteristic equation may not be immediately obvious.
  • #1
Roni1985
201
0

Homework Statement


How can I annihilate the following ?
4e-2t*cos(2t)

Homework Equations





The Attempt at a Solution



I know that if I want to annihilate e-t
it would be (D-1) and to annihilate cos(2t) it would be (D2+22)

but what happens if they are multiplied ?
how do I annihilate this ?
I tried something and I'm not sure it's correct but I got
(D2+4)/(D-2)
?
 
Physics news on Phys.org
  • #2
If you wanted to annihilate, for example, etsin(3t) or etcos(3t), the annihilator would be D2 - 2D + 10.

The characteristic equation for the differential equation y'' - 2y' + 10y = 0, or (D2 - 2D + 10)y = 0, is r2 - 2r + 10 = 0. The roots of this latter equation are r = 1 +/- 3i. The connection between etsin(3t) and etcos(3t) on the one hand, and 1 +/- 3i on the other, is not coincidental.
 
  • #3
Mark44 said:
If you wanted to annihilate, for example, etsin(3t) or etcos(3t), the annihilator would be D2 - 2D + 10.

The characteristic equation for the differential equation y'' - 2y' + 10y = 0, or (D2 - 2D + 10)y = 0, is r2 - 2r + 10 = 0. The roots of this latter equation are r = 1 +/- 3i. The connection between etsin(3t) and etcos(3t) on the one hand, and 1 +/- 3i on the other, is not coincidental.

I am having a little problem following your explanation.

Say this is your differential equation:
y'' - 2y' + 10y =etcos(3t)

or for the left part only
(D2 - 2D + 10)y
and what you are basically saying is that the left part of the equation => (D2 - 2D + 10) annihilates etcos(3t)

so it should look this way :
(D2 - 2D + 10)*(D2 - 2D + 10)y =(D2 - 2D + 10)*etcos(3t)

<=>(D2 - 2D + 10)2y=0

Thank you.
 

FAQ: How can I use the annihilator method to solve for 4e-2t*cos(2t)?

What is the annihilator method for solving ODEs?

The annihilator method is a technique used to solve ordinary differential equations (ODEs). It involves finding a differential operator, called the annihilator, that when applied to the given ODE, results in a simpler equation that can be easily solved.

When is the annihilator method most useful?

The annihilator method is most useful when the ODE contains terms that can be eliminated by the application of a differential operator. It is particularly effective for solving non-homogeneous linear ODEs with constant coefficients.

How do you find the annihilator of an ODE?

To find the annihilator of an ODE, you must first identify the terms that need to be eliminated. Then, you apply the corresponding differential operator to those terms. For example, if the ODE contains a term in the form of e^x, you would apply the operator D-e^x to eliminate it.

Can the annihilator method be used for all types of ODEs?

No, the annihilator method is most effective for solving linear ODEs with constant coefficients. It may not work for nonlinear or variable coefficient ODEs.

Is the annihilator method the only way to solve ODEs?

No, there are various other methods for solving ODEs, such as separation of variables, substitution, and the method of undetermined coefficients. The annihilator method is just one approach that can be used, depending on the type of ODE.

Similar threads

Back
Top