- #1
Albert1
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Quadrilateral ABCD
given :$\overline{AB}=a ,\overline{BC}=y ,\overline{CD}=b
\,\, and \,\, \overline{AD}=x$
prove :
$4S \leq (a+b)\times(x+y)$
(where S is the area of ABCD)
given :$\overline{AB}=a ,\overline{BC}=y ,\overline{CD}=b
\,\, and \,\, \overline{AD}=x$
prove :
$4S \leq (a+b)\times(x+y)$
(where S is the area of ABCD)