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The current of a regenerative shock absorber is modeled by
I = -5e^(-0.5t) cos t - 10e^(-0.5t) sin t
Given that the charge, q, in an electrical current is related to, I by I = dq/dt and that at t = 0 the charge of the regenerative shock absorber is q=80, find the charge when t = 5
Hint= need to find the derivative of e^(-0.5t) cos t
Part B
Due to safety specifications the long term percentage charge of the circuit cannot exceed 92%. By first determining the lim as n approaches infinite, q(t). calculate whether the charge will exceed the safety limit
discuss results
please
I = -5e^(-0.5t) cos t - 10e^(-0.5t) sin t
e^(-0.5t) cos t
I tried working it out by doing intergration by parts but I can't seem to get past that point
Second Question:
Develop a mathematical model that would lengthen the time until the shock stabilised by the given time. T= 2.51 show mathematical analysis of the situation
d(t) = -5e^(-5t) cos (10t) is the original equation for a deflection of a rod in centimetres where t is time and d is deflection.
More info:
once a rod is released at time 0, it will spring back towards rest position where deflection is 0. It will go past rest which is called first rebound before rebounding again, going back through rest. the maximum distance of the rod below the rest position after this first rebound (dm) is used to measure the performance of the damper. dividing this rebound distance by the initial displacement (which is 5cm) gives the rebound ratio for that particular damper. if the ratio is below 1% the damper is working correctly
I = -5e^(-0.5t) cos t - 10e^(-0.5t) sin t
Given that the charge, q, in an electrical current is related to, I by I = dq/dt and that at t = 0 the charge of the regenerative shock absorber is q=80, find the charge when t = 5
Hint= need to find the derivative of e^(-0.5t) cos t
Part B
Due to safety specifications the long term percentage charge of the circuit cannot exceed 92%. By first determining the lim as n approaches infinite, q(t). calculate whether the charge will exceed the safety limit
discuss results
please
Homework Equations
I = -5e^(-0.5t) cos t - 10e^(-0.5t) sin t
e^(-0.5t) cos t
The Attempt at a Solution
I tried working it out by doing intergration by parts but I can't seem to get past that point
Second Question:
Develop a mathematical model that would lengthen the time until the shock stabilised by the given time. T= 2.51 show mathematical analysis of the situation
d(t) = -5e^(-5t) cos (10t) is the original equation for a deflection of a rod in centimetres where t is time and d is deflection.
More info:
once a rod is released at time 0, it will spring back towards rest position where deflection is 0. It will go past rest which is called first rebound before rebounding again, going back through rest. the maximum distance of the rod below the rest position after this first rebound (dm) is used to measure the performance of the damper. dividing this rebound distance by the initial displacement (which is 5cm) gives the rebound ratio for that particular damper. if the ratio is below 1% the damper is working correctly