How can the equation be modified to create a perfect ellipse on the graph?

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In summary, the graph of the equation cos(a) + cos(b) = cos(a + b) shows an ellipse-like shape, but it is not a perfect ellipse. This is because the equation is not specifically for an ellipse, but for any smooth function that satisfies certain conditions. To get a perfect ellipse, you can adjust the parameters to satisfy those conditions. The Desmos graph also shows that the equation looks like an ellipse until the parameter a is close to 1.
  • #1
highmath
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The graph of the equation:
cos(a) + cos(b) = cos(a + b)
show when the equation is valid.

The graph show an ellipses-like and not like a "perfect" ellipse. Why?
If I want to change the equation, what can I do to get a perfect ellipse?!
 
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  • #2
This equation is discussed on Math.StackExchange. The accepted answer says that it is indeed not an ellipse, but the solutions to any equation $f(x,y)=\text{const}$ around $(x_0,y_0)$ looks like an ellipse for a smooth function $f$ if $\frac{\partial f}{\partial x}(x_0,y_0)=\frac{\partial f}{\partial y}(x_0,y_0)=0$ and \(\displaystyle \begin{vmatrix}\frac{\partial^2f}{\partial x^2}f(x_0,y_0)&\frac{\partial^2f}{\partial x\partial y}f(x_0,y_0)\\\frac{\partial^2f}{\partial x\partial y}f(x_0,y_0)&\frac{\partial^2f}{\partial y^2}f(x_0,y_0)\end{vmatrix}>0\) (i.e., if $(x_0,y_0)$ is an extremum point of $f$).
 
  • #3
If you move the slider for this Desmos graph, you will see that the graph looks very like an ellipse until the parameter $a$ is quite close to $1$.

[DESMOS]advanced: {"version":5,"graph":{"squareAxes":false,"viewport":{"xmin":-1.3747197653766552,"ymin":-0.9204796366940666,"xmax":6.9623451644014835,"ymax":7.416585293084072}},"expressions":{"list":[{"type":"expression","id":"graph1","color":"#2d70b3","latex":"\\cos x\\ +\\ \\cos y\\ -\\ \\cos\\left(x+y\\right)\\ =\\ a","style":"SOLID"},{"type":"expression","id":"2","color":"#388c46","latex":"a=0","hidden":true,"sliderHardMin":true,"sliderHardMax":true,"sliderMin":"-3","sliderMax":"1","sliderInterval":"0.25","style":"SOLID"}]}}[/DESMOS]
 

FAQ: How can the equation be modified to create a perfect ellipse on the graph?

What is the meaning of cos(a) + cos(b) = cos(a + b)?

Cos(a) + cos(b) = cos(a + b) is an identity in trigonometry that states the sum of two cosine values is equal to the cosine of their sum. In other words, it means that the cosine of the sum of two angles is equal to the sum of the cosines of the two angles.

How is cos(a) + cos(b) = cos(a + b) used in mathematics?

Cos(a) + cos(b) = cos(a + b) is used in solving trigonometric equations and identities, as well as in various applications of trigonometry such as in physics, engineering, and navigation. It is also used in proving other trigonometric identities.

Can cos(a) + cos(b) = cos(a + b) be applied to any values of a and b?

Yes, cos(a) + cos(b) = cos(a + b) holds true for any values of a and b, as long as they are real numbers. This is because the cosine function is defined for all real numbers and the addition of real numbers is commutative.

Is cos(a) + cos(b) = cos(a + b) a special case of a trigonometric identity?

Yes, cos(a) + cos(b) = cos(a + b) is a special case of the sum-to-product identity, which states that cos(a) + cos(b) = 2cos((a+b)/2)cos((a-b)/2). When a = b, the second term becomes 0, resulting in cos(a) + cos(b) = 2cos(a/2)cos(a/2) = 2cos^2(a/2).

How can cos(a) + cos(b) = cos(a + b) be proved?

Cos(a) + cos(b) = cos(a + b) can be proved using the cosine addition formula, which states that cos(a + b) = cos(a)cos(b) - sin(a)sin(b). By substituting this into the original identity, cos(a) + cos(b) = cos(a)cos(b) - sin(a)sin(b), we can simplify to get cos(a) + cos(b) = cos(a + b).

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