- #1
regnar
- 24
- 0
Find the volume of the solid obtained by rotating the region bounded by the given curves about the line y=1.
y = [tex]\sqrt[4]{x}[/tex] , y = xI couldn't figure out if a should subtract one from x or from y = [tex]\sqrt[4]{x}[/tex]. I don't know if I'm doing this right I tried subtracting it from x and got a negative area.
I also used this formula:
[tex]\pi[/tex][tex]\int[/tex]r^2 h
y = [tex]\sqrt[4]{x}[/tex] , y = xI couldn't figure out if a should subtract one from x or from y = [tex]\sqrt[4]{x}[/tex]. I don't know if I'm doing this right I tried subtracting it from x and got a negative area.
I also used this formula:
[tex]\pi[/tex][tex]\int[/tex]r^2 h