- #1
Peetch
- 5
- 0
I have been reading on these forums for a bit learning about vehicles and their physics. I still have a few questions and do want to clarify some things as well.
I am trying to simulate a vehicle give some basic info you can find online about any car or vehicle. I know Peak HP and the corresponding RPM, I know peak torque and the corresponding RPM and i know the idle RPM and HP. given that info i make a linear graph for the HP of the engine by using the HP = (Torque * RPM)/5252 and its variations. Once i have a close approximation of the HP curve given the vehicles RPM i can then calculate the engines output torque.
I know the gear ratios of the vehicle as well. and they are as follows:
Gear 1 = 3.49
Gear 2 = 1.86
Gear 3 = 1.41
Gear 4 = 1.00
Gear 5 = 0.75
Gear 6 = 0.65
Differential Gear = 1.7
now using EngineTorque * CurrentGear * Differential I will get the torque to the drive wheels.
The part I am a little lost on is if the vehicle is in second gear with the engine RPM at 3000 and using our liner graph the approximated engine HP is 141.47. With that we will take Torque = (141.47 * 5252)/3000 so our engine output torque will be 247.67. Now applying that through the transmission and so on the torque to the drive wheels will be 247.67 * 1.86 * 1.7 and that equals 783.13.
Now this is where I am kinda lost. I know that the torque going to the wheel is 783.13 but how does that apply with MOI and AA and the vehicles speed. Here is other data i know but not sure how to apply it.
Vehicle Weight: 5200 pounds
Wheel Radius: 1.6 feet
again this is my understanding if I an wrong pleas correct any of my steps and please help me understand how I go from torque to the wheel to the speed/movement of the vehicle
I am trying to simulate a vehicle give some basic info you can find online about any car or vehicle. I know Peak HP and the corresponding RPM, I know peak torque and the corresponding RPM and i know the idle RPM and HP. given that info i make a linear graph for the HP of the engine by using the HP = (Torque * RPM)/5252 and its variations. Once i have a close approximation of the HP curve given the vehicles RPM i can then calculate the engines output torque.
I know the gear ratios of the vehicle as well. and they are as follows:
Gear 1 = 3.49
Gear 2 = 1.86
Gear 3 = 1.41
Gear 4 = 1.00
Gear 5 = 0.75
Gear 6 = 0.65
Differential Gear = 1.7
now using EngineTorque * CurrentGear * Differential I will get the torque to the drive wheels.
The part I am a little lost on is if the vehicle is in second gear with the engine RPM at 3000 and using our liner graph the approximated engine HP is 141.47. With that we will take Torque = (141.47 * 5252)/3000 so our engine output torque will be 247.67. Now applying that through the transmission and so on the torque to the drive wheels will be 247.67 * 1.86 * 1.7 and that equals 783.13.
Now this is where I am kinda lost. I know that the torque going to the wheel is 783.13 but how does that apply with MOI and AA and the vehicles speed. Here is other data i know but not sure how to apply it.
Vehicle Weight: 5200 pounds
Wheel Radius: 1.6 feet
again this is my understanding if I an wrong pleas correct any of my steps and please help me understand how I go from torque to the wheel to the speed/movement of the vehicle