- #1
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Homework Statement
http://img18.imageshack.us/img18/4180/82081641.jpg
http://img14.imageshack.us/img14/2650/26169677.jpg
http://img13.imageshack.us/img13/6657/diagramsx.jpg
Homework Equations
The Attempt at a Solution
For the first one, the solutions are different from mine, but here is what I did:
Note [itex]\times[/itex] denotes the cross-product
[tex]v_B=\vec{\omega_B} \times \vec{r_{CB}}[/tex]
[tex]v_B=2.5k \times 0.045j=-0.1125j[/tex]
[tex]v_A=\vec{\omega_A} \times \vec{r_{OA}}[/tex]
[tex]v_A= 3k \times 0.06i=0.18j
[tex]\vec{v_{AB}}=\vec{v_A}-\vec{v_B}=0.1125i+0.18j[/tex]
Now, [itex]\vec{r_{AB}}= 0.09i+0.12j[/itex]
[tex]\vec{\omega_{AB}} \times \vec{r_{AB}}= w_{AB}k \times (0.09i+0.12j)[/tex]
[tex]\Rightarrow \vec{v_{AB}}=-0.12 \omega_{AB}i+0.09\omega_{AB}j[/tex]
and if I compare components I get two different values for [itex]\omega[/itex]
For the second question, the first thing I'd do is get the moment of inertia of the rod about the centre using (1/12)mL^2 and then say Ia=Torque to get a, then use F=ar to get the force needed. But I do not know if I should assume the rod is uniform and use the parallel axis theorem.
For the third one, I am not too sure how to start that one. All I know that I can get from reading the question is the moment of inertia about the axis using the radius of gyration.
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