How Can We Calculate the Pressure Inside a Sphere With Varying Density Gas?

In summary, the task is to estimate the pressure inside a sphere filled with unknown gas. The density of the sphere changes as we go deeper inside using the formula ρ=ρo*(1-r/R), where R is the radius of the sphere and r is a variable. The gas has a molar mass of 2.7 g/mol and the mass of the whole sphere is 3.3*1050 kg. The gas is ideal and the equations used are pV=nRT and p=F/A. The method involves calculating the force of gravity of an infinitesimal layer inside the sphere and integrating to find the pressure at the center of the sphere. However, it is unclear if the method is too complex or if there are
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Homework Statement



I have a sphere filled with unknown gas. I have to estimate the pressure inside of it.

  • The tricky part is that density of the sphere changes as we go deeper inside of it with the given formula:
    ρ=ρo*(1-r/R), where R is radius of the sphere and is known: R=5*1010m, and r is a variable.
  • Gas has mol mass m=2.7 g/mol.
  • Mass of the whole sphere is M=3.3*1050 kg.
  • Gas is ideal.

Homework Equations



  • pV=nRT
  • p=F/A


The Attempt at a Solution



The force of gravity of an infinitesimal layer of thickness dr inside the sphere at some radius r caused by the inner sphere is:

dF=GmM/r2 where m is the mass of the infinitesimal layer and M is the mass of inner part of the sphere.

Mass m=V*ρ=4*PI*r2o*(1-r/R)*dr
Mass M=4/3*PI*r3o*(1-r/R)

so dF=G*16/3*PI2*r3o2*(1-r/R)2*dr

dp=dF/A
dp=dF/4*PI*r2
dp=4/3*PI*G*ρo2*(1-r/R)2*r*dr

so
p(r)=4/3*PI*G*ρo2*[tex]\int[/tex](1-r/R)2*r*dr from r to R

After making the calculations I will put p(r=0) and get the pressure inside the sphere. Is my method good?
 
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  • #2
too hard or did I do something wrong?
 
  • #3


I would say that your method is a good start, but it may not give an accurate estimation of the pressure inside the sphere. There are a few assumptions and simplifications that may affect the accuracy of your calculation.

Firstly, assuming that the gas is ideal may not accurately represent the behavior of the unknown gas inside the sphere. Real gases can deviate from ideal behavior, especially at high pressures.

Secondly, using the formula for density changing with depth may not be accurate for a gas, as gases tend to expand to fill their container. This formula is more commonly used for liquids or solids.

Additionally, the force of gravity may not be the only force acting on the gas inside the sphere. There may be other external forces, such as electromagnetic forces, that could affect the pressure.

Overall, your method provides a good starting point, but to get a more accurate estimation of the pressure inside the sphere, you may need to consider these factors and possibly use more advanced equations and techniques. It may also be helpful to conduct experiments or gather more information about the gas inside the sphere to improve the accuracy of your estimation.
 

FAQ: How Can We Calculate the Pressure Inside a Sphere With Varying Density Gas?

1. What is the definition of pressure inside a sphere?

The pressure inside a sphere is the force per unit area exerted on the interior surface of the sphere. It is typically measured in units of Pascals (Pa) or pounds per square inch (psi).

2. How is pressure inside a sphere calculated?

The pressure inside a sphere can be calculated using the equation P = F/A, where P is pressure, F is force, and A is the surface area of the interior of the sphere. Additionally, the ideal gas law, PV = nRT, can be used to calculate pressure if the temperature, volume, and number of moles of gas inside the sphere are known.

3. What factors affect the pressure inside a sphere?

The pressure inside a sphere is affected by the amount of gas or fluid inside, the volume of the sphere, the temperature of the gas or fluid, and the type of gas or fluid present. Other factors, such as external forces, can also impact the pressure inside a sphere.

4. How does pressure inside a sphere change with depth?

The pressure inside a sphere increases with depth, as there is more weight of the gas or fluid above pushing down on the interior surface. This is due to the force of gravity acting on the particles in the gas or fluid, causing them to exert pressure on the surface below.

5. Can the pressure inside a sphere be negative?

Yes, the pressure inside a sphere can be negative if there is a vacuum or low-pressure environment inside the sphere. In this case, the force per unit area exerted on the interior surface will be in the opposite direction, causing a negative pressure value.

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