How Can We Determine the Number of Abelian Groups of Order p^n?

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In summary, the conversation discussed an exercise involving abelian groups of order p^n, where p is a prime number, and filling out a table for n = 2 to n = 8. The number of groups was determined by the different ways of writing p^n. The conversation also mentioned the possibility of finding a formula for this relation and the connection to partition numbers. Overall, the conversation provided insights into the concept of abelian groups and their relationship to partition numbers.
  • #1
DarkEternal
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I was doing an exercise for my algebra class dealing with the number of abelian groups of order p^n, where p is a prime number, up to isomorphism. i had to fill out a table for n = 2 to n = 8. for example, for n = 2,3,4,5,6,7,8, the number of groups = 2,3,5,7,11,15,22, respectively. essentially, the different ways one can write p^n. for example, for p^5, one can write p^5, p^4 p, p^3 p p, etc... although not part of the question, i was wondering if there was an easy way to work out a formula for this relation given any n? seems interesting, but i haven't come across it yet.
 
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Yes, these are partition numbers of some kind: the number of ways of writing n as the sum of integers.

2=1+1=0+2
3=1+1+1=1+2=0+3
4=1+1+1+1=1+1+2=2+2=1+3=0+4

If you think about it an abelian p group is specified by the number of subgroups of order p, p squared, p cubed and so on, and it becomes clear where the numbers come from.
 
  • #3


It is definitely interesting to see the different factorizations of p^n and how they correspond to the number of abelian groups of order p^n. This exercise highlights the importance of understanding the structure of prime numbers and their powers.

To answer your question about finding a formula for this relation, there is actually a well-known formula called the partition function that can help with this. The partition function, denoted as p(n), gives the number of ways to write a positive integer n as a sum of positive integers, disregarding the order of the summands. In other words, it counts the number of partitions of n.

For example, p(5) = 7, which is the number of ways to write 5 as a sum of positive integers: 5, 4+1, 3+2, 3+1+1, 2+2+1, 2+1+1+1, 1+1+1+1+1. This corresponds to the 7 different factorizations of p^5 that you mentioned.

In general, for a prime number p, the number of abelian groups of order p^n, up to isomorphism, is given by p(n), where n is the power of p. So for p=2, the number of abelian groups would be 1,2,4,7,11,16, etc. This relation is also known as the number of partitions of n with distinct parts.

While there may not be a simple formula for this relation, the partition function can help us understand the patterns and relationships between different factorizations of p^n. I hope this helps in your exploration of this interesting topic!
 

FAQ: How Can We Determine the Number of Abelian Groups of Order p^n?

What is a factorization of p^n and why is it important?

A factorization of p^n is the expression of a number, p, raised to a certain power, n, as a product of smaller numbers. It is important because it allows us to understand the properties and relationships of numbers and to solve mathematical problems involving powers and exponents.

How many different factorizations of p^n are there?

There are infinitely many different factorizations of p^n, as p and n can take on any value. However, for a specific value of p and n, there may be a limited number of unique factorizations.

How do you find all the different factorizations of p^n?

To find all the different factorizations of p^n, you can use methods such as prime factorization, factoring by grouping, or the distributive property. It may also be helpful to use a factor tree or a factorization calculator.

What is the difference between prime factorization and other factorization methods?

Prime factorization is the process of breaking down a number into its prime factors, which are numbers that can only be divided by 1 and itself. Other factorization methods involve breaking down a number into any combination of smaller numbers, not necessarily limited to prime numbers.

Can different factorizations of p^n have the same result?

Yes, different factorizations of p^n can result in the same value. For example, 6 can be factored as 2 x 3 or 1 x 6, both of which result in the value of 6. However, the factors themselves may be different, which can be important in certain mathematical problems.

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