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ital_dj
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[SOLVED] General question about mirrors
I'll give you a question as an example. My question to you isn't about solving the question, as you'll see below.
A thumb of height 8cm is held in front of a concave mirror of focal length 10cm. The image formed is 12cm from the vertex of the mirror. Find:
[I'll give you the one that applies to the question]
c) the size of the image
[tex]\frac{hi}{ho}[/tex] = [tex]\frac{-di}{do}[/tex]
I plugged in 8cm under ho, 12cm under di, and 60cm under do (calculated previously), and came out with the answer -1.6cm. The answer in the book says it's positive 1.6cm. I've made this mistake previously, and was wondering how I can differentiate between the positive and negative solution.
Thanks in advance.
I'll give you a question as an example. My question to you isn't about solving the question, as you'll see below.
Homework Statement
A thumb of height 8cm is held in front of a concave mirror of focal length 10cm. The image formed is 12cm from the vertex of the mirror. Find:
[I'll give you the one that applies to the question]
c) the size of the image
Homework Equations
[tex]\frac{hi}{ho}[/tex] = [tex]\frac{-di}{do}[/tex]
The Attempt at a Solution
I plugged in 8cm under ho, 12cm under di, and 60cm under do (calculated previously), and came out with the answer -1.6cm. The answer in the book says it's positive 1.6cm. I've made this mistake previously, and was wondering how I can differentiate between the positive and negative solution.
Thanks in advance.