How can you differentiate xe^x csc x without using the product rule?

In summary, the conversation is about using the product rule to solve a problem with three variables. The suggested solution is to extend the product rule to three terms and then continue with the problem. The person asking for help expresses gratitude for the clarification.
  • #1
r_swayze
66
0
I don't really know how to even start this problem because I don't think the product rule would work here since there are three variables, right?

Here is my attempt at it:

xe^x csc x

xe^x csc x + xe^x (-csc x cot x)

xe^x (csc x - csc x cot x)

Used the product rule and that's what I came up with, can anyone give me a hint at what the first step is at least?
 
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  • #2
You can easily extend the product rule to three terms. (fgh)'=f'gh+fg'h+fgh'.
 
  • #3
thanks, that makes a lot more sense :)
 

FAQ: How can you differentiate xe^x csc x without using the product rule?

What is the derivative of xe^x csc x?

The derivative of xe^x csc x is xe^x cot x + e^x csc x.

How do you simplify xe^x csc x?

To simplify xe^x csc x, you can use the product rule and the derivative of csc x, which is -csc x cot x, to get xe^x cot x - e^x csc x cot x.

Can you use the quotient rule to differentiate xe^x csc x?

No, the quotient rule is used to differentiate functions of the form f(x)/g(x). Since xe^x csc x is a product of two functions, you need to use the product rule to differentiate it.

What is the domain of xe^x csc x?

The domain of xe^x csc x is all real numbers except for values that make csc x undefined, such as x = 0, pi, 2pi, etc.

How can you use logarithmic differentiation to differentiate xe^x csc x?

You can use logarithmic differentiation to differentiate xe^x csc x by taking the natural logarithm of both sides and then using the chain rule and product rule to simplify the expression. This method is helpful when dealing with complicated functions.

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