- #1
Euge
Gold Member
MHB
POTW Director
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- 244
Here is this week's problem!
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Let $\Bbb k$ be a field. Suppose $A \in M_n(\Bbb k)$ such that $\operatorname{trace}(AM) = 0$ for all $M \in M_n(\Bbb k)$. Prove $A = 0$. Furthermore, show that the linear transformation $L_B : M_n(\Bbb k) \to M_n(\Bbb k)$ given by $L_B(X) = BX$ is an isometry with respect to the inner product $\langle X,Y\rangle = \operatorname{trace}(XY^T)$ if and only if $B$ is orthogonal.
Note: Due to the fact there there are essentially two problems this week, I have simplified this problem so that you may, if you wish, rely on the theory of eigenvalues and eigenvectors of matrices over fields.
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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
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Let $\Bbb k$ be a field. Suppose $A \in M_n(\Bbb k)$ such that $\operatorname{trace}(AM) = 0$ for all $M \in M_n(\Bbb k)$. Prove $A = 0$. Furthermore, show that the linear transformation $L_B : M_n(\Bbb k) \to M_n(\Bbb k)$ given by $L_B(X) = BX$ is an isometry with respect to the inner product $\langle X,Y\rangle = \operatorname{trace}(XY^T)$ if and only if $B$ is orthogonal.
Note: Due to the fact there there are essentially two problems this week, I have simplified this problem so that you may, if you wish, rely on the theory of eigenvalues and eigenvectors of matrices over fields.
-----
Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
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