How Can You Solve a Differential Equation Involving Exponential Drag Force?

In summary: You can use the following steps: First find the integral of the function from thepoint to the point, then Integrate the function from the point to the point.In summary, the particle is moving with a constant velocity, but at a certain point a force is applied to slow it down. The force is given by F=ma, where m is the mass of the particle, and c is the speed of light. The acceleration due to the force is given by:acceleration = F/m
  • #36
MichaelTam said:
Are there any way to learn more calculus to get more strategy?
It looks like you need to reread integration basics, paying attention to bounds and to definite and indefinite integrals.
 
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  • #37
I got v(t) = -1/c ln( e^(-c v_0) + bc/m t ).
 
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  • #38
ThEmptyTree said:
I got v(t) = -1/c ln( e^(-c v_0) + bc/m t ).
Good.
 
  • #39
MichaelTam said:
Homework Statement:: MIT pretest.
Relevant Equations:: 𝐅⃗=−𝑏𝑒^(𝑐𝑣)𝐢̂ , find v(t), by using differential equation of F=maHello, would you mind sharing what course this is? I am familiar with edx but can’t find it
 
  • #42
This problem becomes more complex if we alter the initial condition of ##v_0## to be not parallel to x-axis but to have some other direction. For example if ##v_0## is in the y-axis then the differential equation becomes $$m\frac{dv_x}{dt}=-be^{c\sqrt{v_0^2+v_x^2}}$$ and who can solve this
 
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