- #1
sunflowerzz
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Homework Statement
A circuit contains a single 250 pF capacitor hooked across a battery. It is desired to store three times as much energy in a combination of two capacitors by adding a single capacitor to this one. How would you hook it up, and what would its value be?
Homework Equations
PE = (1/2) CV^2
The Attempt at a Solution
PE(final) = 3PE(initial)
so then:
(1/2)CV^2 = 3 * (1/2) CV^2
Not sure where to go from here? I would think that if it is three times as much energy, then it should be 3 times the capacitance 3C = 3 * 250 pF = 750 pF but this isn't correct