How Deep Is the Lake After Dropping a Ball from 30 Meters?

[miamiheat5]

A heavy ball is dropped into a lake from a height of 30.0m above the water. it hits the water with a certain velocity and continues to sink to the bottom of the lake at this same constant velocity. It reaches the bottom of the lake 10.0s after it was dropped. How deep is the lake.


And the solution i got:


vf^2=vi^2+2ad
vf^2=2(-9.81)(30.0)
vf=24.3m/s


d=vt
=(24.3)(10)
=24.3m deep

 

[chaoseverlasting]

24.3*10=243m

 

[m2003]

Based on the given information and using the equation vf^2=vi^2+2ad, we can determine the final velocity (vf) of the ball when it hits the water. From this, we can calculate the time it takes for the ball to reach the bottom of the lake using the equation d=vt. By substituting the values, we can calculate the depth of the lake to be 24.3m. This assumes that there is no air resistance or other external factors affecting the ball's motion.