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I recently have been studying how the SE solutions produce orbitals in the atom. I understand that we are not to think of these classically as actual orbits, however, I am looking for a little clarification on a couple things. For one, it is relatively easy to see how two electrons may share a 1s spherical orbital. But what about a p orbital? Is each electron confined to one or the other lobes of the dumbbell? After all, there is a zero probability that the electron can be found between the lobes and therefore a zero probability that it can smoothly transition (classically at least) between the two.
I know that this is QM and that we are supposed to allow for these counterintuitive things to happen, but has there actually been any experiments that conclusively demonstrate that, in a half-filled p orbital, the SAME electron is found zipping around both lobes of the orbital. Or is it typically found in just one? In addition, are there any experiments that tell us whether two electrons filling a p orbital can be found in either lobe? Or that both can be found in one lobe at the same time and not the other? I’m guessing that if measurements have found that both electrons demonstrating opposite spins have an equal probability of being in either lobe at any given time, then I’ll have to accept that. I’m just looking for a less counterintuitive solution or visualization.
I know that this is QM and that we are supposed to allow for these counterintuitive things to happen, but has there actually been any experiments that conclusively demonstrate that, in a half-filled p orbital, the SAME electron is found zipping around both lobes of the orbital. Or is it typically found in just one? In addition, are there any experiments that tell us whether two electrons filling a p orbital can be found in either lobe? Or that both can be found in one lobe at the same time and not the other? I’m guessing that if measurements have found that both electrons demonstrating opposite spins have an equal probability of being in either lobe at any given time, then I’ll have to accept that. I’m just looking for a less counterintuitive solution or visualization.