- #1
James889
- 192
- 1
Hi,
I have two voltages given as v1(t) = 20cos([tex]\omega[/tex]t - 45)
and v2(t) = 10sin([tex]\omega[/tex]t + 60)
My task is to add them on the single form Vcos([tex]\omega[/tex]t + [tex]\theta[/tex])
The first part is relativley easy:
The phasors are v1 = 20[tex]\angle[/tex]-45)
and v2 = 10[tex]\angle[/tex]-30)
so i have 20[tex]\angle[/tex]-45) + 10[tex]\angle[/tex]-30)
20cos(-45) = 14.14
20sin(-45) = -j14.14
10cos(-30) = 8.66
10sin(-30) = -j5
Add those up and you have 22.8 -j19.14
But how do i get this in polar form?
I have two voltages given as v1(t) = 20cos([tex]\omega[/tex]t - 45)
and v2(t) = 10sin([tex]\omega[/tex]t + 60)
My task is to add them on the single form Vcos([tex]\omega[/tex]t + [tex]\theta[/tex])
The first part is relativley easy:
The phasors are v1 = 20[tex]\angle[/tex]-45)
and v2 = 10[tex]\angle[/tex]-30)
so i have 20[tex]\angle[/tex]-45) + 10[tex]\angle[/tex]-30)
20cos(-45) = 14.14
20sin(-45) = -j14.14
10cos(-30) = 8.66
10sin(-30) = -j5
Add those up and you have 22.8 -j19.14
But how do i get this in polar form?