How Do I Balance This Chemical Equation?

In summary, the conversation discusses the mixing of Mg(NO_{3})_{2} and Na_{3}PO_{4} solutions, with a focus on determining the mass of the product Mg_{3}(PO_{4})_{2}. The process involves using the densities of the solutions to calculate the amount of moles for each reactant, and then balancing the equation to determine the amount of product. The conversation also touches on determining compound formulas and the importance of ensuring a neutral salt molecule. However, the given numbers and formulas do not seem to align, creating confusion and a need for further clarification.
  • #1
Dell
590
0
dont know why all the index numbers came above the letters in my post but they are meant to be below.

250ml of Mg(NO[tex]_{3}[/tex])[tex]_{2}[/tex] with a density of 45g/L are mixed with 75 ml Na[tex]_{3}[/tex]PO[tex]_{4}[/tex] with a density of 30g/l.
what is the mass of the product Mg[tex]_{3}[/tex](PO[tex]_{4}[/tex])[tex]_{2}[/tex]

what i did was, using the densities, found out the masses of the molecules and then using the masses found out the amount of given mol's of each.
what i get is

0.071 mol Mg(NO[tex]_{3}[/tex])[tex]_{2}[/tex]
0.0137 mol Na[tex]_{3}[/tex]PO[tex]_{4}[/tex]

giving me a ratio of about 5:1

so

5Mg(NO[tex]_{3}[/tex])[tex]_{2}[/tex]+ Na[tex]_{3}[/tex]PO[tex]_{4}[/tex] ----> Mg[tex]_{3}[/tex](PO[tex]_{4}[/tex])[tex]_{2}[/tex]

problem comes here, i need to balance the equation to continue,
but i have missing elements?? what do i do?

once i have balanced the equation i can see how many mols of Mg[tex]_{3}[/tex](PO[tex]_{4}[/tex])[tex]_{2}[/tex] i have and then i fan work out its mass.

how do i add up the missing elements?
 
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  • #2
Dell said:
dont know why all the index numbers came above the letters in my post but they are meant to be below.

Don't use tex for single character formatting, use [ sub][ /sub] and [ sup][ /sup] tags (no spaces after [).

250ml of Mg(NO[tex]_{3}[/tex])[tex]_{2}[/tex] with a density of 45g/L are mixed with 75 ml Na[tex]_{3}[/tex]PO[tex]_{4}[/tex] with a density of 30g/l.
what is the mass of the product Mg[tex]_{3}[/tex](PO[tex]_{4}[/tex])[tex]_{2}[/tex]

Something is wrong, these solutions will have a density of around 1000 g/L, numbers you have posted don't make sense. Are you sure you have copied numbers/question correctly?

5Mg(NO[tex]_{3}[/tex])[tex]_{2}[/tex]+ Na[tex]_{3}[/tex]PO[tex]_{4}[/tex] ----> Mg[tex]_{3}[/tex](PO[tex]_{4}[/tex])[tex]_{2}[/tex]

problem comes here, i need to balance the equation to continue,
but i have missing elements?? what do i do?

This is double exchange reaction with two reactants and two products. Think in terms of ions present in the solution before reaction. Precipitate removes some of these ions, others are left. Those left define other product.
 
  • #3
Borek said:
This is double exchange reaction with two reactants and two products. Think in terms of ions present in the solution before reaction. Precipitate removes some of these ions, others are left. Those left define other product.


so my balanced equation will come to ----> Mg3(PO4)2 + something,, is this right,,
how can i know what the "something" is? can i just add in the missings ones to balance it? how can i know how to write them?
 
  • #4
How did you know your reactants formulas were Mg(NO3)2 and Na3PO4?
 
  • #5
that was given in the question
 
  • #6
Do you know any systematic method for determining compound formula? Especially for salts the method is relatively simple and is based on the fact that salt molecule must be neutral.
 
  • #7
havent learned that yet, is there no other way i can solve this? are my assumptions thus far correct??
could you tell me what the formula is meant to be so i can continue with the excercise
 
  • #8
Even if I will give you the formula of the compound, your data so far (numbers given as densities) don't make sense.

Are you sure these are densities, and not amounts of substance dissolved per litre of the solution?

Can you name the substances mixed?
 

FAQ: How Do I Balance This Chemical Equation?

What is the difference between a chemical equation and a chemical formula?

A chemical equation is a representation of a chemical reaction using symbols and formulas to show the reactants and products involved. A chemical formula, on the other hand, is a shorthand notation for a specific chemical compound or molecule. Chemical equations show how compounds react with each other, while chemical formulas indicate the type and number of atoms present in a compound.

How do you balance a chemical equation?

To balance a chemical equation, you need to make sure that the number of atoms of each element on the reactant side is equal to the number of atoms on the product side. This is achieved by adjusting the coefficients (numbers in front of the formulas) of the compounds in the equation. The law of conservation of mass states that matter cannot be created or destroyed, so balancing an equation ensures that the same number of atoms are present on both sides of the reaction.

What is the purpose of using formulas in chemistry?

Formulas in chemistry are used to represent the composition of chemical compounds and molecules. They provide valuable information about the type and number of atoms present in a compound, which is essential for understanding their properties and behavior. Formulas also allow for easy communication and understanding among scientists and students when discussing chemical reactions and compounds.

Can chemical equations be written for all types of reactions?

Yes, chemical equations can be written for all types of reactions, including synthesis, decomposition, single replacement, double replacement, and combustion reactions. However, some reactions may be more challenging to represent due to their complexity or the involvement of multiple steps. In these cases, scientists may use a series of equations to fully illustrate the reaction process.

What is the difference between a molecular formula and an empirical formula?

A molecular formula represents the exact number of atoms of each element in a molecule, while an empirical formula provides the simplest whole number ratio of atoms in a compound. For example, the molecular formula for glucose is C6H12O6, while the empirical formula is CH2O. Molecular formulas are used for covalent compounds, while empirical formulas are more commonly used for ionic compounds.

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