How do I calculate the necessary speed and direction for a plane to offset wind?

[Charles C]

I know that this should be simple, but I really can't find out how to do this:
A pilot needs to fly at 600km/hr on a bearing of 240 degrees to be on time and on course. A wind is blowing from the west at 60km/hr. In what direction and at what speed should she fly her plane to offset the effect of the wind?

One question I have is when it says "on a bearing of 240 degrees", do you count clockwise or counterclockwise?

I will greatly appreciate any help.

Eh, I think I posted in the wrong area, feel free to to move this.

 

[Shooting Star]

Bearings are generally given as the angle that is measured clockwise from north. Now you can use the formula for relative velocity.

 

[Charles C]

Ok, I think I got it:
http://img137.imageshack.us/img137/8330/83884348hr7.jpg

 

[Shooting Star]

Could you explain the diagram?

 

[Charles C]

the speed of the plane is 600, so 600sin30 is 300 and 600cos30 is 519.6. The wind coming from the west is 60, so to compensate for that, I add the 60 to the 300 and get 360. Then I use the Pythagorean theorem to get 632.
Actually, I think I may have done it wrong cause I'm pretty sure I'm supposed to get a different angle.

 

[Shooting Star]

You have to compenste by adding 60 to 600*cos 30. Then you'll get the correct answer.

 

[Charles C]

You have to compenste by adding 60 to 600*cos 30. Then you'll get the correct answer.

So it would be 652.64 with theta=30?

 

[Shooting Star]

I'm leaving that to you. You know how to multiply. I have to do something now.

 

[Shooting Star]

Quite correct. Now find the angle in which the plane has to go.