How do I compute magnetic flux?

In summary: B*A*sinθ*dθ/dt = 1* pi * 10 * 10 * sin(10 deg + 20 deg * t) * 20 degIn summary, the question asked for the magnitude of induced emf in a circular loop with a radius of 10 cm rotating in a constant magnetic field of 1 T at an instant when the angle between the magnetic field and the normal axis is 10 degrees and increasing at a rate of 20 degrees/s. The formula for magnetic flux is explained as the product of magnetic field and perpendicular surface area, and the formula for induced emf is given as the negative derivative of magnetic flux with respect to time. A formula for calculating the surface area is given, but
  • #1
austin007
8
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A circular loop (with a radius of 10 cm) rotattes in a constant magnetic fiels, which has a magnitude of 1 T. At an instant when the angle between the magnetic field and the normal axis (to the plane of the loop) is equal to 10 degrees and is increasing at a rate of 20 degrees/s, what is the magnitude of the induced emf in the loop?

How do I compute magnetic flux? ( I know that farady's law can be used to find emf)
 
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  • #2


Firstly, what do you understand by "magnetic flux"?
 
  • #3


Fightfish said:
Firstly, what do you understand by "magnetic flux"?

It is the product of magnetic field, B and perpendicular surface area to B, A.

I know B which is 1 T, how do I get A especially the angle.
 
  • #4


Consider the projection of the surface area of the loop onto the plane perpendicular to the magnetic field (sort of like the 'shadow'). (You can consider the loop in 2D - a straight line to simplify the analysis)
 
  • #5


Fightfish said:
Consider the projection of the surface area of the loop onto the plane perpendicular to the magnetic field (sort of like the 'shadow'). (You can consider the loop in 2D - a straight line to simplify the analysis)

So is A = pi * r * r cos(10 deg + 20 deg * t) correct?
 
  • #6


austin007 said:
So is A = pi * r * r cos(10 deg + 20 deg * t) correct?
That would be the correct A (perpendicular) for any time t if the rate of increase remains constant over time. However, it would not help you solve the problem. You should formulate it in a generic fashion: A = pi * r * r cos (theta), solve for dA/dt, before substituting the relevant values into obtain the solution at that point.
 
  • #7


austin007 said:
So is A = pi * r * r cos(10 deg + 20 deg * t) correct?
At any instant the magnetic flux φ = B*A*cosθ.
So induced emf e = - dφ/dt = -(-B*A*sinθ*dθ/dt )
 

FAQ: How do I compute magnetic flux?

What is magnetic flux?

Magnetic flux is a measure of the total magnetic field passing through a given area. It is represented by the symbol Φ and is measured in units of webers (Wb).

How do I calculate magnetic flux?

Magnetic flux can be calculated by multiplying the magnetic field strength (B) by the area (A) through which it passes, and then taking the cosine of the angle between the field and the area. The equation for magnetic flux is Φ = B*A*cos(θ).

What is the difference between magnetic flux and magnetic field?

Magnetic field refers to the strength and direction of a magnetic force, while magnetic flux is a measure of the total magnetic field passing through a given area. In other words, magnetic field is a vector quantity, while magnetic flux is a scalar quantity.

How does magnetic flux affect electronic devices?

Magnetic flux can affect electronic devices by inducing currents in them. These induced currents can cause interference and damage to the devices. This is why electronic devices often have shielding to protect them from external magnetic fields.

Can magnetic flux be negative?

Yes, magnetic flux can be negative. This occurs when the angle between the magnetic field and the area through which it passes is greater than 90 degrees (θ > 90°), resulting in a negative value for the cosine in the equation Φ = B*A*cos(θ). Negative magnetic flux is often seen in situations where the magnetic field is directed away from the area, such as in a solenoid or a transformer.

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