- #1
mathdad
- 1,283
- 1
Factor the expression.
3(x + h)^4 - 48(x + h)^2
I believe I can factor out 3(x + h)^2.
If so, we then have the following:
3(x + h)^2[(x + h)^2 - 16]
I think (x + h)^2 - 16 is the difference of two perfect squares.
If so, then it factors out to be [(x + h) - 4][(x + h) + 4].
Answer: 3(x + h)^2[(x + h) - 4][(x + h) + 4].
Correct?
3(x + h)^4 - 48(x + h)^2
I believe I can factor out 3(x + h)^2.
If so, we then have the following:
3(x + h)^2[(x + h)^2 - 16]
I think (x + h)^2 - 16 is the difference of two perfect squares.
If so, then it factors out to be [(x + h) - 4][(x + h) + 4].
Answer: 3(x + h)^2[(x + h) - 4][(x + h) + 4].
Correct?