How Do I Find the Coefficient of Friction Using Potential Energy?

In summary, the conversation is about a homework assignment involving a data table with information on initial and final positions, velocities, and angle. The question asks for the coefficient of friction to be found using a formula related to potential energy. The person is feeling confused and asks for help.
  • #1
hanagasumi
11
0
Hi, I really need help with my homework!

I had a home work, it is like:
I have a data table, that has

Initial Position: 1.652m from the sensor
Final Position: 0.977m from the sensor

Initial Velocity: 0.003m/s
Final Position: 1.366m/s

Angle: 27 degrees
g = -9.8m/s^2

U represent the variable for coefficient of friction

The question asks me to find the coefficient of friction, by using the formula according to the potential energy, it's like

gh= v^2+ UcosAngle*d*g

I'm so confused! Please help me@!
Thank you in advance!
 
Physics news on Phys.org
  • #2


Just use

[tex]\frac{1}{2}mv^2 + F_R d = mgh[/tex]


and find the frictional force FR and then see how FR relates to the coefficient of friction.
 
  • #3


thank you !
 

FAQ: How Do I Find the Coefficient of Friction Using Potential Energy?

What subject does your homework pertain to?

My homework is in the subject of science.

Can you help me with all aspects of my homework?

As a scientist, my expertise lies in the field of science. So I can assist you with any questions related to that subject.

How long will it take for you to help me with my homework?

It depends on the complexity of the questions and the amount of help you need. But I will try my best to assist you as quickly as possible.

Can you explain complex concepts in a simple manner?

Yes, as a scientist, it is important for me to communicate complex concepts in a clear and understandable manner. I will do my best to break down difficult concepts for you.

Is there a limit to the number of questions you can help me with?

I am happy to assist you with as many questions as you have, but please keep in mind that I may have other responsibilities and may not be able to provide immediate help for every single question.

Back
Top