How do i move get rid of a fraction like this?

[dbzsongoku]

Hi,
Usually for question like 1/(e^x) I can get rid of the fraction by writing it as e^-x. FOr a question like (e^x+1)/e^x how do I do this? It simplifies down to e^-x+1 but I don't get how to do it.
thanks

 

[quasar987]

Because

$$\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}$$

 

[gazzo]

edit: dextercioboy: ooh true. sorry!

 

[dextercioby]

$$\frac{e^x+1}{e^x} = \frac{e^x}{e^x} + \frac{1}{e^x} = 1 + \frac{1}{e^x} = e^{-1} + 1$$

edit: gah, quasar you're too fast

You have a typo...And besides,the idea was to make him solve the exercise,not doing it for him...


Daniel.

 

[hypermorphism]

Hi,
Usually for question like 1/(e^x) I can get rid of the fraction by writing it as e^-x. FOr a question like (e^x+1)/e^x how do I do this? It simplifies down to e^-x+1 but I don't get how to do it.
thanks

A direct answer to your exact question is (e^x + 1)*e^-x, just like your 1/e^x example. Don't forget the distributive property of multiplication over addition.