- #1
tmt1
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Hi I'm working on a problem for calculus
and I got this
2x + 3 (y-x)^2 * (y'-1) = 0 .
And then, in the answer part it says I have to get to here, which I'm not sure how to do.
2x + 3 (y-x)^2 * y'- 3 (y-x)^2 = 0 ,
Thanks,
Tim
and I got this
2x + 3 (y-x)^2 * (y'-1) = 0 .
And then, in the answer part it says I have to get to here, which I'm not sure how to do.
2x + 3 (y-x)^2 * y'- 3 (y-x)^2 = 0 ,
Thanks,
Tim