- #1
curiousguy
- 5
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I have been trying to figure this out for 2 weeks.
A helicopter is begins its horizontal motion 2500 ft from the center of a targe 30 ft above the target traveling at 40mph. The target ( a pile of boxes) is stacked 15 ft high off the ground. At the appropriate time, a person is to jump out of the helicopter and hit the target. For the purpose of this problem, my professor says do not consider the horizontal speed of the jumper. I am to find the quad formula and parabola that states 1) when the person should jump to hit the target, 2) the speed of the jumper upon impact with the target. HELP! I am soooo stuck. I cannot get the quad formula for this! I did convert mph to ft per sec. Is it rational to use 16 ftpersec^2 as "g", acceleration due to gravity? When I use it, and graph the parabola it doesn't come close to hitting the target. When I try to graph the parabola from a couple of coordinates I know, it won't do it. HELP!
A helicopter is begins its horizontal motion 2500 ft from the center of a targe 30 ft above the target traveling at 40mph. The target ( a pile of boxes) is stacked 15 ft high off the ground. At the appropriate time, a person is to jump out of the helicopter and hit the target. For the purpose of this problem, my professor says do not consider the horizontal speed of the jumper. I am to find the quad formula and parabola that states 1) when the person should jump to hit the target, 2) the speed of the jumper upon impact with the target. HELP! I am soooo stuck. I cannot get the quad formula for this! I did convert mph to ft per sec. Is it rational to use 16 ftpersec^2 as "g", acceleration due to gravity? When I use it, and graph the parabola it doesn't come close to hitting the target. When I try to graph the parabola from a couple of coordinates I know, it won't do it. HELP!
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