- #1
Mr. Hiyasaki
- 9
- 0
In this lab we dropped coffee filters from a given height (3 M) and want to determine their terminal velocity
My problem is I don't know how to solve the log thing given.
we have terminal velocity, V, in the formula
Mg = bV^n which I change to V=(Mg/b)^(1/n)
then to solve this I go
ln V = (1/n)[ln(M) + ln(g) - ln(b)]
I know the Mass, I have an average velocity I can substitute in for V and g, as usual, is 9.81 m/s^2
b is a constant dependent on the shape of the object, or "shape factor" and n is the power of the velocity (which I am guessing should come out somewhere close to 2, although assumptions are always bad)
when i go n = [ln(M) + ln(g) - ln(b)]/[ln (V)] everything comes out crazy and makes no sense
my physics teacher told me to disregard all laws of logs and just go [ln(M) + ln(g) - ln(b) - ln (V)]
when I put it in my calculator and solve simultaneously it comes out and the numbers make sense, but I have no idea what my calculator is doing to get those answers.
My problem is I don't know how to solve the log thing given.
we have terminal velocity, V, in the formula
Mg = bV^n which I change to V=(Mg/b)^(1/n)
then to solve this I go
ln V = (1/n)[ln(M) + ln(g) - ln(b)]
I know the Mass, I have an average velocity I can substitute in for V and g, as usual, is 9.81 m/s^2
b is a constant dependent on the shape of the object, or "shape factor" and n is the power of the velocity (which I am guessing should come out somewhere close to 2, although assumptions are always bad)
when i go n = [ln(M) + ln(g) - ln(b)]/[ln (V)] everything comes out crazy and makes no sense
my physics teacher told me to disregard all laws of logs and just go [ln(M) + ln(g) - ln(b) - ln (V)]
when I put it in my calculator and solve simultaneously it comes out and the numbers make sense, but I have no idea what my calculator is doing to get those answers.