How do I solve for the position vector using 2-D vector analysis?

In summary: If you use t=14 and plug it in the original position vector, shouldn't the J-component of the position vector be 0? Reasoning being that for θ to be 0, the J-component has to be 0?
  • #1
princeton_wu
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Homework Statement



http://imgur.com/wNusHOw

Homework Equations



I have the solutions and how they did it. THey took the deriv for the velocity vector, and then using t=0 and t=14, they found e=3.5 and f=-0.125

The Attempt at a Solution



I understand the math, but I don't understand why this is correct
1) why did they take the velocity vector?
2) if I plug e and f back into the position vector, and using t=14 i should get θ=0, ie, j-component is 0. But I don't. So what am I doing wrong?
 
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  • #2
welcome to pf! :smile:

hi princeton_wu! welcome to pf! :smile:
princeton_wu said:
1) why did they take the velocity vector?

because the graph gives you the direction of the velocity vector
2) if I plug e and f back into the position vector, and using t=14 i should get θ=0, ie, j-component is 0. But I don't.

yes you do …

j-component = e + 2ft = 3.5 - 3.5 = 0 :wink:
 
  • #3
tiny-tim said:
hi princeton_wu! welcome to pf! :smile:because the graph gives you the direction of the velocity vectoryes you do …

j-component = e + 2ft = 3.5 - 3.5 = 0 :wink:

i mean the r vector; shouldn't the J-component of the r-vector be 0 @ t=14? this way, the angle @ t=14 would be 0.
 
  • #4
princeton_wu said:
i mean the r vector; shouldn't the J-component of the r-vector be 0 @ t=14? this way, the angle @ t=14 would be 0.

i'm not following your reasoning :confused:

the graph shows that vj = 0 (because θ = 0) at t = 14, it says nothing about r :smile:
 
  • #5
tiny-tim said:
i'm not following your reasoning :confused:

the graph shows that vj = 0 (because θ = 0) at t = 14, it says nothing about r :smile:

sorry, I'm confused too :-p

If you use t=14 and plug it in the original position vector, shouldn't the J-component of the position vector be 0? Reasoning being that for θ to be 0, the J-component has to be 0?

thanks for your patience tiny tim!
 
  • #6
(just got up :zzz:)
princeton_wu said:
Reasoning being that for θ to be 0, the J-component has to be 0?

but θ (given in the graph) is stated to be the angle of the velocity vector …

i don't understand what you think that has to do with the position vector :redface:
 
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  • #7
I mulled over it last night and I finallly got it. My problem stemmed from the fact that I didn't realize that a t vs θ graph is a velocity graph). Thanks Tim! :smile:
 

FAQ: How do I solve for the position vector using 2-D vector analysis?

1. What is 2-D vector analysis?

2-D vector analysis is the study of vectors in two-dimensional space. It involves analyzing and manipulating quantities with both magnitude and direction, such as displacement, velocity, and force.

2. Why is 2-D vector analysis important?

2-D vector analysis is important because it is used in many fields of science and engineering, including physics, mathematics, and computer graphics. It helps us understand and predict the behavior of objects in two-dimensional space.

3. How do I perform 2-D vector analysis?

To perform 2-D vector analysis, you will need to have a basic understanding of vectors, including their properties and operations. You will also need to know how to represent vectors using coordinates and how to manipulate them using mathematical equations.

4. What are some common applications of 2-D vector analysis?

2-D vector analysis has many practical applications, such as in navigation, motion analysis, and engineering design. It is also used in computer graphics to create realistic 2-D images and animations.

5. What are some tips for solving 2-D vector analysis problems?

Some tips for solving 2-D vector analysis problems include drawing accurate diagrams, breaking down complex vectors into simpler components, and using the appropriate equations and formulas. It is also important to pay attention to units and directions when performing calculations.

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