How do I solve the ODE: x(1-x^2)+ky^2/y?

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In summary, the conversation is about solving a differential equation using the integrating factor method. The equation is rearranged and rewritten in terms of u, where u = y^2. The correct integrating factor is determined to be e^(-x), which was initially thought to be e^(-kx). The conversation ends with a note from the moderator reminding helpers to follow the guidelines when providing homework help.
  • #1
Juggler123
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I need to solve the following ODE

[tex]\frac{dy}{dx}=\frac{x(1-x^2)+ky^2}{y}[/tex]

I don't know what is the correct method to use though.

Any help would be brilliant, thanks.
 
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  • #2
Let u = y^2. Rearrange the equation as such: [tex]yy^{\prime}-ky^2 = x(1-x^2) [/tex]. Write the left hand side as a linear combination of u' and u.
 
  • #3
O.k using

[tex]u=y^{2}[/tex]

then does the equation become

[tex]\frac{du}{dx}-u=\frac{x(1-x^2)}{k}[/tex]

I still don't know where to go from here (if this is even right!)

Am I missing something really easy here?
 
  • #4
YOu can use the integrating factor method. If I'm not mistaking, the IF is e^(-x).
 
  • #5
wouldnt the integrating factor be e^-kx?
 
  • #7
It's e^(-kx) as you say, you made a mistake in your equation above.
 
  • #8
Moderator's note: thread moved to Homework & Coursework Questions.

Helpers please take note, the normal forum guidelines on giving homework help apply.
 

FAQ: How do I solve the ODE: x(1-x^2)+ky^2/y?

What does "ODE" stand for?

ODE stands for Ordinary Differential Equation.

What does the "x(1-x^2)" term represent in the equation?

This term represents a function of x, where the value of x is multiplied by the quantity (1-x^2).

What does the "ky^2/y" term represent in the equation?

This term represents a function of y, where the value of y is multiplied by the constant k.

How do you solve this ODE?

To solve this ODE, you can use various methods such as separation of variables, substitution, or integrating factors. The specific method used will depend on the form of the equation.

What are the possible solutions to this ODE?

The solutions to this ODE will depend on the given initial conditions. Generally, the solutions will be in the form of a function that satisfies the equation and the initial conditions.

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