- #1
Bensky
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Need help on a vector problem by tomorrow. :(
A woman walks 277. m in the direction 41.6° east of north, then 171 m directly east. Find
(a) her resultant vector displacement from the starting point
There were other parts to the question which I got right, I can't seem to get this one.
None except the pythagorean theorem:
In this case, D=[tex]\sqrt{Dx^2 + Dy^2}[/tex]
D1X=cos(41.6°) * 277
D1X=207.1400711
D2X=171
D1Y=sin(41.6°) * 277
D1Y=183.9075609
D2Y=0
Dx=378.14
Dy=183.9075604
D=sqrt(378.14^2+183.9075609^2)
D=420.49 =~ 420.5
Ok, so I got 420.5 and plugged in it. Nope, the computer says it's wrong. I tried rounding it to 421 and that was wrong also. I don't think I made any math errors, what am I doing wrong?
Homework Statement
A woman walks 277. m in the direction 41.6° east of north, then 171 m directly east. Find
(a) her resultant vector displacement from the starting point
There were other parts to the question which I got right, I can't seem to get this one.
Homework Equations
None except the pythagorean theorem:
In this case, D=[tex]\sqrt{Dx^2 + Dy^2}[/tex]
The Attempt at a Solution
D1X=cos(41.6°) * 277
D1X=207.1400711
D2X=171
D1Y=sin(41.6°) * 277
D1Y=183.9075609
D2Y=0
Dx=378.14
Dy=183.9075604
D=sqrt(378.14^2+183.9075609^2)
D=420.49 =~ 420.5
Ok, so I got 420.5 and plugged in it. Nope, the computer says it's wrong. I tried rounding it to 421 and that was wrong also. I don't think I made any math errors, what am I doing wrong?