How Do I Verify Legendre Polynomials and Their Orthogonality?

  • Thread starter Thread starter ilikephysics
  • Start date Start date
  • Tags Tags
    Polynomials
Click For Summary
Legendre polynomials are solutions to a specific differential equation, and verifying their solutions requires substituting the integer l into the equation for each polynomial. To demonstrate orthogonality, one must compute integrals of the form ∫ from -1 to 1 of Pl(x)Pm(x) dx for pairs of l and m, ensuring that when l is not equal to m, the result is zero. The process involves selecting different values for l and m, such as l=1 and m=2, and performing the integrals for multiple pairs. Each polynomial must be evaluated by plugging in the corresponding l value into the differential equation. This approach confirms both the solution and orthogonality properties of the Legendre polynomials.
ilikephysics
Messages
18
Reaction score
0
I know that legendre polynomials are solutions of the differential equation is (1-x^2)d^2y/dx^2 - 2x dy/dx+l(l+1)y=0 where l is an integer. The first five solutions are P0(x)=1, P1(x)=x, P2(x)=3/2x^2-1/2, P3(x)=5/2x^3-3/2x, P4(x)=35/8x^4-15/4x^2+3/8

The problem is that I don't understand what the problem is telling me to do. It says to show that each of the polynomials Pl(x) solves the differentil equation with its particular value l. Do I just plug in l? For example, for P0(x)=1, would I plug in 1 for x and 0 for l? I'm really confused.


Another problem is that I have to show by doing 10 integrals that if l is not equal to m, that integral from -1 to 1 dxPl(x)Pm(x)=0 so that these polynomials are orthogonal on the interva1 [-1,1].

Do I just take a value for l and one for m 10 times. So for the first integral, m=1 and n=2?
 
Physics news on Phys.org
y_l = P_l(x)

is a solution to the differential equation

(1-x^2)\frac{d^2y}{dx^2} - 2x \frac{dy}{dx} + l(l+1)y = 0

They make up pairs. When l = 2, we have y_2 = P_2(x) is a solution to the differential equation given if 2 is plugged in for l (meaning the last term is 6).

If l = 15, then we have to plug in l = 15 into y_l and l = 15 into the differential equation. Then the solution y_15 will solve the differential equation made when we substitute 15 for l.

cookiemonster
 
z solves an equation, f, if f(z)=0, o yes you just plug in the z which is P_l into the equation defining the l^th legendre polynomial.

secondly you must do the integrals for every pair of numbers (l,m) where l and m are one of 1,2,3,4
 

Similar threads

  • · Replies 30 ·
2
Replies
30
Views
1K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
6
Views
1K
Replies
3
Views
9K