How Do Parallel Current-Carrying Wires Affect Each Other?

In summary, the problem involves calculating the force on one wire in an equilateral triangle of parallel wires carrying a current of 50 A each. Using the equation F= 2*10^-7(I1)(I2)/d, the force on the top wire is calculated to be 5.0*10^-3 N in the direction between wires b and c, which is attractive due to the currents being in the same direction. The question arises whether the resultant force on the top wire, which would point straight down, needs to be calculated using the parallelogram rule or if the answer can simply be left as is. Using the cosine rule, the resultant force is found to be (3^1/2)(5*
  • #1
steve12
7
0

Homework Statement


hi,im a bit confused by the following question.i think i have a fairly good idea of most of the solution but the actual wording of the question is stil throwing me.

Q: 3 parallel wires,arranged in the form of an equilateral triangle,of side length 10cm,each carry a current of 50 A in the same direction.Calculate the force on anyone wire due to the other two.


Homework Equations


I used the equation F= 2*10^-7(I1)(I2)/d
a
and arranged wires as follows: *


b* c*

with wires going into page.

The Attempt at a Solution


i calculated the force on the top wire,a, due to b and c:
F=2*10^-7(50)(50)/0.1 = 5.0*10^-3 N in each case,along the line joining a to b and a to c

so this force F is attractive as the currents are in the same direction,yes?
what i am wondering is if i have to calculate the resultant force on a,that is,use for eg the parallelogram rule to find the resultant force, which would point in the direction straight down,or can i simply leave the ans. as is??

is there some sort of convention for expressing this direction or can i just say in the direction indicated on a diagram?

i used the cosine rule and found that the resultant force is (3^1/2)(5*10^-3)N in the direction pointing straight down so that the vector would bisect bc as shown in diagram,does this make sense?
thanks steve:smile:
 
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  • #2
ok that didnt work out,wires are meant to look like this:

...a*


b* .... c*



ignore dots
 
  • #3



Hi Steve,

It seems like you have a good understanding of the problem and have used the correct equation to calculate the force on wire a due to wires b and c. You are correct in saying that the force is attractive since the currents are in the same direction.

As for the direction of the resultant force, you can express it either as the direction indicated on the diagram or as the direction pointing straight down. Both are acceptable ways of expressing the direction.

Using the cosine rule to find the resultant force and its direction makes sense. It is important to consider the direction of the resultant force in this problem since the wires are arranged in an equilateral triangle.

Overall, your solution seems to be correct and you have a good understanding of the problem. Keep up the good work!
 

FAQ: How Do Parallel Current-Carrying Wires Affect Each Other?

What is the formula for calculating the force on a wire due to current?

The formula for calculating the force on a wire due to current is F = I * L * B, where F is the force in Newtons, I is the current in Amperes, L is the length of the wire in meters, and B is the magnetic field strength in Tesla.

How does the direction of the current affect the force on the wire?

The direction of the current will determine the direction of the force on the wire. If the current and magnetic field are both in the same direction, the force will be attractive, and if they are in opposite directions, the force will be repulsive.

What is the relationship between the strength of the magnetic field and the force on the wire?

The force on the wire is directly proportional to the strength of the magnetic field. This means that as the magnetic field strength increases, the force on the wire will also increase.

Can the force on a wire due to current be zero?

Yes, the force on a wire due to current can be zero if the wire is placed parallel to the magnetic field. In this case, the wire experiences no force as the magnetic field is not acting perpendicular to the wire.

How does the length of the wire affect the force on it due to current?

The force on a wire due to current is directly proportional to the length of the wire. This means that as the length of the wire increases, the force on it will also increase. This relationship is expressed in the formula F = I * L * B, where L is the length of the wire.

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