- #1
hello478
- 165
- 14
- Homework Statement
- question c part ii) power produced by engine
- Relevant Equations
- p= f* v
its by finding the component of weight along slopeBvU said:8628.46 ?
##\ ##
i have attached the question image above..., is it not there? let me check againBvU said:So the slope is given, and so is the mass of the lorry. Given for you , that is.
But my telepathic capabilities are limited and I need a complete problem statement, typed out.
And: what are the directions of 8628.46 and the resistive force ?
##\ ##
The F you need to use in P=Fv is the motive force delivered by the engine. This has to balance the opposing forces, the 5200N of resistance plus the gravitational component.hello478 said:Homework Statement: question c part ii) power produced by engine
Relevant Equations: p= f* v
View attachment 342385
View attachment 342389
ok so in p=fvharuspex said:The F you need to use in P=Fv is the motive force delivered by the engine. This has to balance the opposing forces, the 5200N of resistance plus the gravitational component.
Depends what you mean by "total force". As you wrote, since the speed is constant the total force on the truck is zero.hello478 said:ok so in p=fv
the f would always be total force?
yeah the net force would be zeroharuspex said:Depends what you mean by "total force". As you wrote, since the speed is constant the total force on the truck is zero.
Yes, that being the static frictional force on the tyres. We can consider that the motive force provided by the engine, though in reality what the engine provides is a torque.hello478 said:yeah the net force would be zero
but here... we would have to use the force which is causing the body to move
Not sure what you mean by that. In the general case the truck is accelerating, so we have ##F_{net}=F_{static}+F_{resist}=ma##, ##F_{resist}## being negative. So the engine power would be ##F_{static}v=(ma-F_{resist})v##.hello478 said:(the total force, sum of resistive forces) with that velocity???
is this explanation fine?
i meant that we would multiply the force which causes to move the lorry with the velocity it createsharuspex said:Not sure what you mean by that.
You don't have to care what creates the velocity. What matters is that a force ##\vec F## is exerted at a point on a body while that point is moving with velocity ##\vec v##. The power transferred is ##\vec F\cdot\vec v##.hello478 said:i meant that we would multiply the force which causes to move the lorry with the velocity it creates
Power is the rate at which work is done or energy is transferred. When a force is applied to an object causing it to move, power can be calculated as the product of the force and the velocity at which the object moves in the direction of the force. Mathematically, Power (P) = Force (F) × Velocity (v).
Velocity directly affects power because power is the product of force and velocity. As velocity increases, for a constant force, the power also increases. Conversely, if velocity decreases, the power decreases, assuming the force remains constant.
No, power cannot be generated without force. Power is the rate of doing work, and work requires a force to be applied over a distance. Without force, no work is done, and consequently, no power is generated.
If you know the power and velocity, you can calculate the force using the formula Force (F) = Power (P) / Velocity (v). This relationship shows that for a given power, if the velocity increases, the force decreases, and if the velocity decreases, the force increases.
If both force and velocity are doubled, the power increases by a factor of four. This is because power is the product of force and velocity. Mathematically, if the original power is P = F × v, then doubling both force and velocity gives the new power as P' = (2F) × (2v) = 4(F × v) = 4P.