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Charles Link said:I think you figured out that the minus charge must be placed between the two positive charges. Both forces are attractive. The first charge pulls charge 3 to the left, giving it a negative sign. The second charge pulls charge 3 to the right=that force is positive.
Meanwhile you need an exponent of 2 on the distances in the denominator.
Your algebra is also incorrect. e.g. ## 6/(4-2) \neq 6/4-6/2 ##.
Charles Link said:I think you figured out that the minus charge must be placed between the two positive charges. Both forces are attractive. The first charge pulls charge 3 to the left, giving it a negative sign. The second charge pulls charge 3 to the right=that force is positive.
Meanwhile you need an exponent of 2 on the distances in the denominator.
Your algebra is also incorrect. e.g. ## 6/(4-2) \neq 6/4-6/2 ##.
That formula only gives the magnitude. The vector form includes r as a vector, e.g. ##\frac{kq_1q_2}{r^3}\vec r##. For the two cases, the r vector is pointing opposite ways.JoeyBob said:I get the right answer as you've said when I make one positive and fix my algebra, but could you explain further why its positive? I understand it pulls the charge to the right, but I was under the impression that, from the equation below, it was the charges that delineated a positive or negative sign.
haruspex said:That formula only gives the magnitude. The vector form includes r as a vector, e.g. ##\frac{kq_1q_2}{r^3}\vec r##. For the two cases, the r vector is pointing opposite ways.
May I add my two-penn’orth?JoeyBob said:Are they not both negative though, because q1*q3 and q2*q3 are both negative?
Fundamental forces are the physical interactions that govern the behavior of matter and energy in the universe. These forces include gravity, electromagnetism, strong nuclear force, and weak nuclear force.
If charges are placed along a line, the net force at a point will depend on the magnitude and direction of the charges. If the charges are equal and opposite, the net force will be zero at the point. If the charges are not equal and opposite, the net force will be non-zero and will depend on the distance between the charges and the strength of the charges.
A net force of zero at a point means that the forces acting on an object at that point are balanced and there will be no acceleration. This is known as equilibrium and is an important concept in physics and engineering.
Yes, charges can be placed along a line to create a net force of zero at any point. This is known as Coulomb's Law and it states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
If the charges are moved along the line, the net force at a point will also change. This is because the distance between the charges and the strength of the charges will change, resulting in a different net force. The net force will be zero when the charges are placed at specific distances from each other, as determined by Coulomb's Law.