- #1
kholdstare121
- 10
- 0
I'm taking high school physics right now, and we're doing kinematics in one dimension.
Well I've been stuck on this word problem for days and stumbled across this
forum on a google search.
Thought maybe you could help. Anyway it is:
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Two soccer players start from rest, 48m apart. They run directly toward each other, both players accelerating. The first player has an acceleration whose magnitude is 0.50 m/s^2. The second player's acceleration has a magnitude of 0.30 m/s^2.
(a) How much time passes before they collide?
(b)At the instant they collide, how far has the first player run?
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I've tried to tackle this as any other algebra distance=rate*time problem (but with some physics equation involved)
I attempted to get the final velocity of both runners by using the equation
Vf^2=vi^2+at
where vf=final velocity and vi=intitial.
I used '48m' as the value for distance when I did this
Then when I get my final velocity I'd figure out the average velocity for both runners.
Then tackle the problem by adding their individual rate*time together to get rt(of the first guy)+rt(second guy)=48m ,Attempting to get the time they collide from that.
BUT, apparently by plugging in 48m in the physics equation gave me a bad final velocity, therefore a bad time.
I know the correct answer for part a is 11 seconds, but don't know how it's obtained. Please I would be greatful if anyone could help.
I'll also try to clear this up if anyone's confused.
Thanks.
Well I've been stuck on this word problem for days and stumbled across this
forum on a google search.
Thought maybe you could help. Anyway it is:
--------------------------------------------------------------
Two soccer players start from rest, 48m apart. They run directly toward each other, both players accelerating. The first player has an acceleration whose magnitude is 0.50 m/s^2. The second player's acceleration has a magnitude of 0.30 m/s^2.
(a) How much time passes before they collide?
(b)At the instant they collide, how far has the first player run?
--------------------------------------------------------------
I've tried to tackle this as any other algebra distance=rate*time problem (but with some physics equation involved)
I attempted to get the final velocity of both runners by using the equation
Vf^2=vi^2+at
where vf=final velocity and vi=intitial.
I used '48m' as the value for distance when I did this
Then when I get my final velocity I'd figure out the average velocity for both runners.
Then tackle the problem by adding their individual rate*time together to get rt(of the first guy)+rt(second guy)=48m ,Attempting to get the time they collide from that.
BUT, apparently by plugging in 48m in the physics equation gave me a bad final velocity, therefore a bad time.
I know the correct answer for part a is 11 seconds, but don't know how it's obtained. Please I would be greatful if anyone could help.
I'll also try to clear this up if anyone's confused.
Thanks.
Last edited: