How Do Two Stars Orbit Each Other with Equal Masses?

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In summary, using the equation Fg = Gm(star1)m(star2)/r^2 and the given information about the orbital speed and period, the mass of the star was calculated to be 3.59x10^30 kg. This was done by equating F=mv^2/r with Fg = Gm(star1)^2/r^2 and using the values for G and the orbital parameters.
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Masjo
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Their are 2 stars orbiting one another. Their masses are equal. The speed at which they rotate is 220 km/h, and their orbital period is 14.4 days. Find the mass of the Star.



Homework Equations


220km/h = 61.1m/s
14.4 days = 51840s

V= 2pi(r)/T
F=ma
F=mv^2/R
F= m4pi^2r/T^2

Fg= Gm(star1)m(star2)/r^2


These are all the equations I've been using. So far, using V= 2pi(r)/T I can deduce that the radius of the star is 504111.2m and using V=d/t I THINK I can say that the space between the stars is 3167424m, but I am not sure.
I've also tried equating F=mv^2/r with Fg = Gm(star1)^2/r^2, and then found the mass to be 3.616x10^13. I don't think this is right, as my teacher said hint: The mass of the sun is 1.99*10^30 kg.
I know I often make stupid math mistakes, but I can't seem to find out where I went wrong... Can anyone help me?
 
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The mass of the star can be calculated using the equation Fg = Gm(star1)m(star2)/r^2, where G is the gravitational constant (6.67x10^-11 N m^2/kg^2). m(star1) = (Fg x r^2)/(G x m(star2))m(star1) = (6.67x10^-11 x 3167424^2)/(G x 1.99x10^30) m(star1) = 3.59x10^30 kg
 
  • #3


I would first like to commend you on your use of relevant equations to solve this problem. It shows a strong understanding of the concepts involved. However, your calculation for the mass of the star seems to be incorrect. Let's break down the problem and see where the mistake might have occurred.

First, we know that the two stars have equal masses, so let's call their mass m. Using the equation F=mv^2/r, we can equate the force of gravity between the two stars to the centripetal force keeping them in orbit. This gives us:

Fg = mv^2/r = Gm^2/r^2

We can rearrange this equation to solve for m:

m = v^2r/G

Plugging in the given values for v (61.1 m/s) and r (5.0411x10^8 m), and the universal gravitational constant G (6.67x10^-11 N*m^2/kg^2), we get a mass of 3.01x10^30 kg. This is very close to the mass of the sun (1.99x10^30 kg), which makes sense since the given hint was that the mass of the sun is involved in the solution.

So, it seems that the mistake was in your calculation for the radius of the star. It should be 5.0411x10^8 m, not 5.0411x10^5 m. This is because the units for velocity are m/s, not km/h, so your conversion to m/s should have given you a larger value.

In summary, the mass of each star in this system is approximately 3.01x10^30 kg, which is equal to the mass of the sun. This makes sense given that the two stars have equal masses and their orbital period is relatively short. I hope this helps clarify the problem for you. Keep up the good work!
 

FAQ: How Do Two Stars Orbit Each Other with Equal Masses?

How do two stars orbit each other?

Two stars orbit each other due to gravitational forces. The larger star exerts a stronger gravitational pull, causing the smaller star to orbit around it. This is known as a binary star system.

What is the distance between two stars in a binary star system?

The distance between two stars in a binary star system can vary greatly, ranging from a few astronomical units (the distance between the Earth and the Sun) to thousands of astronomical units.

How do scientists study binary star systems?

Scientists study binary star systems through various techniques, including spectroscopy, which measures the light emitted by the stars and reveals their masses, temperatures, and compositions. They also use telescopes to observe the stars' movements and gather data on their orbits.

Can two stars in a binary system merge together?

Yes, two stars in a binary system can merge together, especially if they are close enough and have a significant difference in mass. This can result in a more massive star or a new type of star, such as a blue straggler.

Are binary star systems common in the universe?

Yes, binary star systems are very common in the universe. In fact, it is estimated that about half of all stars in the Milky Way are part of a binary system. They are also found in other galaxies and play a crucial role in the evolution of stars and their surrounding environments.

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