SOLUTION HINTS:gillgill said:how do u solve for n?
nP3=720...n!/(n-3)!=720...do u just start cancelling?
that will be n(n-1)(n-2)=720...but its such a big number...is there another easier way to do it?
gillgill said:how do u solve for n?
nP3=720...n!/(n-3)!=720...do u just start cancelling?
that will be n(n-1)(n-2)=720...but its such a big number...is there another easier way to do it?
The formula for solving n permutations is n! (n factorial).
The value of n in a permutation problem represents the number of objects or items being arranged. It can be found in the given problem or can be determined by counting the number of items in a set.
In most cases, n is a positive integer in a permutation problem. However, in some cases, n can be a decimal or negative number, depending on the context of the problem. It is important to carefully read and understand the problem before determining the value of n.
When there are repeated items in a permutation problem, the formula for solving n permutations changes to n! / (n1! * n2! * ... * nr!), where n1, n2, ..., nr represent the number of repetitions for each item. For example, if there are 3 A's, 2 B's, and 1 C, the formula would be n! / (3! * 2! * 1!).
Yes, you can use a calculator to solve for n permutations. However, it is important to make sure that your calculator has a factorial function and to use parentheses correctly when entering the formula. Alternatively, you can use a permutation calculator or a permutation formula table to find the solution.