- #1
eljose
- 492
- 0
complex integral...
let be the integral [tex]\int_{-i\infty}^{i\infty}\frac{1}{exp(s)-1}ds [/tex] then their poles are [tex] 2n\pi [/tex] my question is How would we calculate this integral? i think that the contribution from the poles is [tex] -{\pi}Res(z_0) [/tex] the main problem i find is when i make the change of variables s=iu so we have the improper integral [tex]\int_{-\infty}^{\infty}\frac{1}{exp(iu)-1}ds [/tex] but it has singularities at 2npi so i don,t think if the first integral will be convergent or not...could someone help?..thanks
let be the integral [tex]\int_{-i\infty}^{i\infty}\frac{1}{exp(s)-1}ds [/tex] then their poles are [tex] 2n\pi [/tex] my question is How would we calculate this integral? i think that the contribution from the poles is [tex] -{\pi}Res(z_0) [/tex] the main problem i find is when i make the change of variables s=iu so we have the improper integral [tex]\int_{-\infty}^{\infty}\frac{1}{exp(iu)-1}ds [/tex] but it has singularities at 2npi so i don,t think if the first integral will be convergent or not...could someone help?..thanks