How do we know ##BF_3## has Lewis structure but ##Al_2S_3## does not?

In summary, the first thing we notice is that we have a metal and a nonmetal, so we would think about an ionic model. These elements form the ions ##Al^{3+}## and ##S^{2-}##. These ions form a lattice structure and we get an ionic crystal. But apparently no bond is perfectly ionic or covalent. The electronegativities of aluminium and sulfur are 1.6 and 2.6, respectively. The difference is 1, which is a relatively low value, indicating a high covalent character to the bond formed. However, I am not sure if this difference in electronegativity is relevant when we are analyzing an ionic compound.
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Homework Statement
My question is about concepts of Lewis structures and VSEPR model. I will go through my reasoning about the following problem and questions will come up along the way.
Relevant Equations
Consider ##Al## and ##S## atoms and reason about the types of bonds formed between such atoms.
The first thing we notice is that we have a metal and a nonmetal, so we would think about an ionic model.

These elements form the ions ##Al^{3+}## and ##S^{2-}##.

These ions form a lattice structure and we get an ionic crystal.

But apparently no bond is perfectly ionic or covalent.

The electronegativities of aluminium and sulfur are 1.6 and 2.6, respectively. The difference is 1, which is a relatively low value, indicating a high covalent character to the bond formed. However, I am not sure if this difference in electronegativity is relevant when we are analyzing an ionic compound. I learned it in the context of ascertaining the ionic character of a covalent bond.

However, if we think in terms of polarization and polarizing power, then we have an ion with a relatively small radius and high charge (##Al^{3+}##) and an anion (##S^{2-}##). We should expect some distortion in the electron cloud of the anion and this occurrence means the bond has relatively high covalent character. This covalent character would be even larger if the anion were a larger, heavier atom. Such atoms have lower effective nuclear charge and more shells and their electron clouds are more easily distorted.

Question 1: Does any of this mean we can form a Lewis structure for a compound like ##Al_2S_3##?

After all, there is a Lewis structure for ##BF_3##, and ##B## forms ##B^{3+}## ions.

Instead of being an ionic compound it is covalent with a central boron that has an incomplete octet. It does, however, have high ionic character since the difference in electronegativity is ##\chi_{F}-\chi_{B}=2##.

Question 2: How do we know we can't have the same thing for ##Al_2S_3##?

Now, I'm asking this from the point of view of Lewis Structures and VSEPR.

It has been frustrating to study these topics because many things seem ad-hoc.

Here is another example

##N_2O##

One rule of thumb is to assume the central atom is of the element with the lowest ionization energy. That would be oxygen.

Apparently (by way of googling this molecule), another rule of thumb is to choose the element with the lowest electronegativity. That would be nitrogen.

So, how in the heck do we ever know, given a formula, what Lewis structure to build?

My guess is that these are all experimental results, and actually there is nothing that tells you whether oxygen or nitrogen is the central atom other than listing out exceptions upon exceptions to basic rules of thumb.

EDIT: just after writing this I realized that ##O## can't be the central atom because of another rule of sorts. If ##O## were the central atom it would have expanded valence. But only p-block atoms of elements in period 3 or later can have expanded valence because these elements have empty d-orbitals.

I just want to make sure that this is really the way to study this stuff. I'm self-studying Chemistry. It seems like a bunch of cases and some rules.

Question 3: Is there a light when one learns about quantum mechanics?

I do have one more question though. When we do write out the Lewis structure of ##N_2O##, we get

1690093077804.png


Question 4: Now, ##N## has five valence electrons. It appears only four are being shared in the structures above, and the fifth one went over to the oxygen. Either that or three electrons are being shared, and the fourth bond uses both electrons from ##N##.
 
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Basically you are discovering that simplified models fail when analyzed too deeply.

At the same time you are using intuitions you have built thanks to these simplified models, so they served their purpose.

And yes, in the end QM should give the final answer. To some extent it does - but you may not like the way it does. With exception of the simplest cases solving Schroedingers equation can be done in two ways - exact (which produces numbers, but no insight) and approximate - which produces insight and generalizations, but in the end they are always limited in their applicability, just like models you are using now.
 
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FAQ: How do we know ##BF_3## has Lewis structure but ##Al_2S_3## does not?

How do we know ##BF_3## has a Lewis structure?

##BF_3## (boron trifluoride) has a Lewis structure because it is a covalent compound where atoms share electrons to achieve stable electron configurations. In its Lewis structure, boron forms three single bonds with three fluorine atoms, resulting in an incomplete octet for boron but a stable arrangement for the molecule.

Why does ##Al_2S_3## not have a Lewis structure?

##Al_2S_3## (aluminum sulfide) is an ionic compound rather than a covalent one. In ionic compounds, electrons are transferred from one atom to another, creating ions that are held together by electrostatic forces. This transfer of electrons does not lend itself to representation by a Lewis structure, which is designed to show shared electrons in covalent bonds.

What is the difference between covalent and ionic compounds in terms of Lewis structures?

Covalent compounds involve the sharing of electrons between atoms to form bonds, which can be represented by Lewis structures showing these shared electrons. Ionic compounds involve the transfer of electrons from one atom to another, forming positive and negative ions that attract each other. Lewis structures are not typically used for ionic compounds because they don't involve shared electron pairs.

Can we represent ionic compounds in any other way if not with Lewis structures?

Yes, ionic compounds are often represented using empirical formulas that show the ratio of ions in the compound, and by using diagrams that illustrate the transfer of electrons and the resulting ions. For example, ##Al_2S_3## can be shown as two aluminum ions (##Al^{3+}##) and three sulfide ions (##S^{2-}##) to indicate the ionic nature of the compound.

Are there exceptions where ionic compounds can be somewhat represented by Lewis structures?

While Lewis structures are primarily used for covalent compounds, some ionic compounds with significant covalent character can be represented by Lewis structures to some extent. However, these representations are often limited and do not fully capture the ionic nature of the compound. It is more accurate to use Lewis structures for purely covalent molecules.

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