How do we know that red-shift is caused by expansion?

In summary, there is evidence that objects in space, such as nebulae and HI or HII clouds, emit spectra that look similar to spectra observed from other objects that undergo radiative recombination.
  • #1
tkyoung75
48
4
TL;DR Summary
Filtration / diffusion of light can cause red-shift, so how did physicists conclude that redshift is due to expansion.
Hi, I am not a cosmologist, but this question has been bugging me for some time.
I am an engineer, and I own an aquarium, at least I owned an aquarium with an awesome LED light.
Under certain conditions, I found that when the blue night light was on, organics in the water would fluoresce, green, and penetration would be reduced.
How do we know that a similar phenomena, not necessarily organic has not occurred to light from the far field. Flouresence, filtration, or some other action on light of shorter wavelengths?
 

Attachments

  • 20160728_095436.jpeg
    20160728_095436.jpeg
    18 KB · Views: 145
  • 20160729_164242.jpeg
    20160729_164242.jpeg
    16.2 KB · Views: 132
Space news on Phys.org
  • #2
What research have you done into modern cosmological models?

Note that you've opened this as an A-level thread, which implies you are looking for responses at postgraduate research level. If you haven't studied cosmology at undergraduate level, then it probably should be a B-level.
 
  • #3
First of all, there really is nothing in intergalactic space that would fluoresce like that so there is that. Cosmological redshift also fits very well with observed effects. Fluorescence would not be able to reproduce an overall shift of the entire spectrum, nor could it explain the Lyman alpha forest.

Other things than standard cosmological effects are also being considered generally when looking at cosmology as a whole. A similar situation occurs for the accelerating expansion where dimming by interstellar dust has been considered as a possible explanation of the relative dimness of supernovae, which is the main evidence for accelerating expansion.
 
  • Like
Likes Bandersnatch, tkyoung75, Klystron and 2 others
  • #4
Greetings,
Orodruin said:
Fluorescence would not be able to reproduce an overall shift of the entire spectrum
That is fundamental. All of the spectral features--from UV to microwave--are shifted the same in the case of the redshift. That fact is of great assistance in the assignments of the spectrum.ES
 
  • Like
Likes artis, tkyoung75 and Vanadium 50
  • #5
tkyoung75 said:
Filtration / diffusion of light can cause red-shift
That is simply not true.

If you look at the Wikipedia page on Redshift you will see this picture

1627079286405.png


The spectral features move. Filters don't do this. Neither does fluorescence.
 
  • Like
Likes niteOwl, tkyoung75 and berkeman
  • #6
tkyoung75 said:
How do we know that a similar phenomena, not necessarily organic has not occurred to light from the far field. Flouresence, filtration, or some other action on light of shorter wavelengths?
1. Spectral lines themselves are redshifted. Any absorption and reemission effect would obliterate the spectral lines instead of preserving them. So you end up with the same spectral 'fingerprint' that certain elements or molecules emit/absorb, except that it has been stretched. There is no other known mechanism that explains this other than redshift.

2. Distant stars, galaxies, and other objects that emit a thermal spectrum, that is, a spectrum that is produced by virtue of an object being hot. Their spectrums are observed to be identical to a non-redshifted spectrum except that it has been 'stretched', which is exactly what we would expect when something is redshifted.

3. Any kind of fluorescence would be incredibly obvious when we look at the spectra of objects in space since the spectrum of a fluorescing object looks like nothing else in nature. We don't see this.
 
  • Like
Likes Dale, tkyoung75, phinds and 1 other person
  • #7
Greetings,
Drakkith said:
the spectrum of a fluorescing object looks like nothing else in nature
I do not think that statement is true.ES
 
  • Like
Likes Dale
  • #8
EigenState137 said:
I do not think that statement is true.
It's possible that I am mistaken. Do you have a counterexample?
 
  • Like
Likes Dale
  • #9
Greetings,

Fluorescence is nothing more than the radiative decay of some set of bound excited states under electric dipole selection rules. The term is generally associated with population of those bound excited states via a radiation source. In condensed media, non-radiative relaxation channels can be fast relative to radiative decay such that the initial population distribution of excited states is significantly altered. That is not the case in low density gas phase systems, particularly with atoms that lack vibrational and rotational degrees of freedom.

The emission spectrum from an emission nebula or HI cloud that is excited by the continuum of a nearby star should therefore look very much like the emission spectrum of a similar object undergoing radiative recombination. The bound excited states are the same, the selection rules are the same. Population distributions and thus relative line strengths, and lineshapes might be different but those would be more subtle effects. Indeed the principal difference is the energy spectrum of the excitation source—does it populate predominately bound states, or is it sufficiently energetic to photoionize the system.

If we agree that astrophysical systems such as nebulae and HI or HII clouds are indeed “objects”, and if we agree that radiative recombination can indeed yield the observed emission spectra associated with such objects, then the spectrum of a fluorescing object can indeed look very much like something else in nature. The difference is in the excitation process, not in the radiative decay process.ES
 
  • Like
Likes Dale
  • #10
My apologies, I was thinking of phosphorescence, not simple fluorescence.
 
  • #11
Thank you all for taking the time to answer my question and providing insight.
Sorry for posting as a post graduate topic. I can see now that it is quite fundamental.
Regards.
 
  • Like
Likes EigenState137, Drakkith, berkeman and 1 other person
  • #12
Greetings,
Drakkith said:
My apologies, I was thinking of phosphorescence, not simple fluorescence.
No apology necessary.

Phosphorescence is indeed a different beast. The closest thing I can think of to phosphorescence would be the electric quadrupole (E2) and magnetic dipole (M1) emission lines associated with collisionally pumped, low-lying metastable states such as [OII], [OIII], [NII], and [SII]. Not phosphorescence, but forbidden transition.ES
 
  • Like
Likes Dale and Drakkith
  • #13
I think @EigenState137 said it best in post #4 as well as @Orodruin in post #3.
If it was just the visible spectrum we are talking about but it's also the CMBR and in each case we get the same result.

@tkyoung75
And even if the intergalactic space was filled with fluorescent dust we would still get similar results to those of the existing and already mentioned "Lyman alpha forest" , because even if the same phosphor is used depending on the distance from Earth it's emission peak would differ so in the end you would get not one but multiple ones, the further the cloud the lower the frequency of the light.PS. Now that I think of it, this would be a cool way to make those older mercury vapor fluorescent tubes seem more natural, they emit multiple peaks but if you redshift those peaks you could smear out the spectrum of the lamp. There is just one problem, this implies your ceiling lamp needs to recede from you close to the speed of light and multiple lamps would need different receding speeds in order to make the spectrum linear.
 

FAQ: How do we know that red-shift is caused by expansion?

What is red-shift and how is it related to expansion?

Red-shift is a phenomenon in which light from distant galaxies appears to be shifted towards the red end of the spectrum. This is due to the expansion of the universe, which causes the wavelengths of light to stretch as it travels through space. The greater the distance, the more pronounced the red-shift.

How do we measure red-shift?

Red-shift is measured using a tool called a spectrometer, which separates light into its component wavelengths. By comparing the observed wavelengths of light from a distant galaxy to the known wavelengths of light emitted by certain elements, we can determine the amount of red-shift and therefore the distance of the galaxy.

What evidence supports the idea that red-shift is caused by expansion?

There are several pieces of evidence that support the idea that red-shift is caused by expansion. One is the observation that the farther away a galaxy is, the greater its red-shift. This is consistent with the idea that the universe is expanding uniformly in all directions. Additionally, the cosmic microwave background radiation, which is the remnant heat from the Big Bang, shows a pattern of red-shift that is consistent with the expansion of the universe.

Could there be other explanations for red-shift besides expansion?

While the evidence strongly supports the idea that red-shift is caused by expansion, there have been alternative theories proposed. Some suggest that the red-shift could be caused by the light passing through interstellar dust or other matter, but this does not account for the consistent pattern of red-shift observed in distant galaxies. Others have proposed modifications to the theory of gravity, but these have not been widely accepted by the scientific community.

How does red-shift support the Big Bang theory?

The Big Bang theory states that the universe began from a single point and has been expanding ever since. The observation of red-shift is consistent with this theory, as it indicates that galaxies are moving away from each other as the universe expands. Additionally, the amount of red-shift observed in distant galaxies corresponds to the expected rate of expansion predicted by the Big Bang theory.

Similar threads

Replies
43
Views
5K
Replies
11
Views
2K
Replies
6
Views
2K
Replies
2
Views
1K
Replies
7
Views
2K
Back
Top